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8090 [49]
2 years ago
6

A farmer plans to fence a rectangular pasture adjacent to a river the pasture must contain 405,000 square meters

Mathematics
1 answer:
jeyben [28]2 years ago
7 0

The dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

Let's suppose x and y are the sides of the rectangular garden and y is the parallel to the river.

Then according to the problem:

2x + y = P ..(1)

P is the perimeter of the rectangle.

xy = 405000  (area of the rectangle)

Plug the value of y in the equation (1) from the above equation.

P(x) = 2x + 405000/x

P'(x) = x—405000/x² = 0

x = 450 m

P''(x) > 0 hence at x = 450 the value of P(x) is minimum.

y = 405000/450

y = 900 m

P(min) = 1800 m

Thus, the dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ4

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sladkih [1.3K]

Answer:

L=21.6in and w=13.6

Step-by-step explanation:

If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8

Area is (width)(Length) = (width)(width+8)

W

----------

| |

| |

| | L = w+8

| |

| |

-----------

A = (w+8)(w)

A = w2 + 8w = 295.

(Problem states that area is 295 sq in)

Need to solve this quadratic equation

w2 +8y - 295 = 0

Factor:

(w - 13.64) (w + 21.64) = 0

So

w - 13.64 = 0. or. w + 21.64= 0

Solve these and get

w = 13.64. or. w = -21.64

Only one that makes sense in real life is the poitive one.

So the dimensions are

Width = 13.64 inches

Length = 21.64 inches

7 0
3 years ago
The length of a rectangle is 5 m less than twice the width, and the area of the rectangle is 52 m^2. Find the dimensions of the
lys-0071 [83]

length is 8m

Width is 6.5m

<u>Explanation:</u>

Let, width = b

So, length = 2b-5

area = 52m^{2}

We know,

area of rectangle = length X width

So, 52m^{2} = (2b-5) X b

On solving the above equation, we get

Width, b = 6.5m

length, l = 8m

4 0
3 years ago
calculate the height at 3 seconds given that the rocket travels 85 feet per second and starts on a launch pad 15 feet of the gro
Airida [17]

Answer:

The height of the rocket at 3 seconds is 270 feet

Step-by-step explanation:

To calculate the height of the rocket at 3 seconds,

First, we will determine the height the rocket has traveled in 3 seconds

The height traveled by the rocket is given by

Height (h) = Velocity (v) × Time (t)

From the question,

The rocket travels 85 feet per second, that is the velocity of the rocket is 85 feet per second,

Now,

v = 85 feet / second

t = 3 seconds

Hence,

Height (h) = 85 feet /second × 3 seconds

Height = 255 feet

∴ the rocket would have traveled 255 feet in 3 seconds,

But, the rocket starts on a launch pad 15 feet of the ground,

Then, the height of the rocket at 3 seconds is

255 feet + 15 feet = 270 feet.

Hence, the height of the rocket at 3 seconds is 270 feet

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