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Deffense [45]
2 years ago
8

What is the sum? startfraction x over x 3 endfraction startfraction 3 over x 3 endfraction 2 over x 3 endfraction five-thirds st

artfraction x 5 over x 3 endfraction startfraction x 5 over 3 x 27 endfraction startfraction 6 x over x 3 endfraction
Mathematics
1 answer:
lakkis [162]2 years ago
7 0

The value of the sum expression \frac{x}{x +3} + \frac{3}{x + 3} is 1

<h3>How to determine the sum?</h3>

The expression is given as:

\frac{x}{x +3} + \frac{3}{x + 3}

Take the LCM of terms of the expression

\frac{x}{x +3} + \frac{3}{x + 3} = \frac{x + 3}{x +3}

Evaluate the quotient of x + 3 and x + 3

\frac{x}{x +3} + \frac{3}{x + 3} = 1

Hence, the value of the sum expression \frac{x}{x +3} + \frac{3}{x + 3} is 1

Read more about expressions at:

brainly.com/question/4142886

#SPJ4

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Step-by-step explanation:

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10 times 11 is 110.

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How much does 6.1 cubic feet of water weigh in pounds
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x=-2.5

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3 0
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Prove that √2 +√5 is irrational
Sindrei [870]

We have to prove that \sqrt{2}+\sqrt{5} is irrational. We can prove this statement by contradiction.

Let us assume that \sqrt{2}+\sqrt{5} is a rational number. Therefore, we can express:

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Let us represent this equation as:

a-\sqrt{2}=\sqrt{5}

Upon squaring both the sides:

(a-\sqrt{2})^{2}=(\sqrt{5})^{2}\\a^{2}+2-2\sqrt{2}a=5\\a^{2}-2\sqrt{2}a=3\\\sqrt{2}=\frac{a^{2}-3}{2a}

Since a has been assumed to be rational, therefore, \frac{a^{2}-3}{2a} must as well be rational.

But we know that \sqrt{2} is irrational, therefore, from equation \sqrt{2}=\frac{a^{2}-3}{2a} the expression \frac{a^{2}-3}{2a} must be irrational, which contradicts with our claim.

Therefore, by contradiction,  \sqrt{2}+\sqrt{5} is irrational.

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