A person invested $7,400 in an account growing at a rate allowing the money to
1 answer:
Answer:
$13,304
Step-by-step explanation:
-We use the compound interest function to determine the rate of growth.
-Given that the amount doubles in 13 years, the annual growth rate is calculated as:
We now substitute this value of i in the compound interest formula equation to solve for future value:
Hence, the future value to the nearest dollar is $13,304
*You can alternatively use the exponential growth function:
This is slightly off by just $1
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The time intervals when the riders could see Niagara falls are; 0.834 < t < 1.416 and (3.084, 3.666)
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From the diagram attached, we can say that;
Period = 2π/k
where;
k = 2π/2.25
k = 8π/9
Thus;
h(t) = -(48/2) cos (8π/9)t + ((48/2) + 0.5)
h(t) = -24cos (8π/9)t + 24.5
Riders can see Niagara falls if they are higher than 41 meters above the ground. Thus;
41 = -24cos (8π/9)t + 24.5
41 - 24.5 = -24cos (8π/9)t
16.5 = -24cos (8π/9)t
-0.6875 = cos (8π/9)t
cos⁻¹0.6875 = (8π/9)t
t = 0.834 min
Thus, time interval is between;
0.834 < t < (2.25 - 0.834)
⇒ 0.834 < t < 1.416 and
(2.25 + 0.834) < t < (2.25 + 1.416)
⇒ (3.084, 3.666)
Read more about Cycle Graphs at; brainly.com/question/24461724
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The rate a computer works is 1/time. Working together, you add the rates.
Let new computer be x, old computer be y.
x = y - 7
Rounded to nearest tenth gives:
x = 23 hours
Let new computer be x, old computer be y.
x = y - 7
Rounded to nearest tenth gives:
x = 23 hours
Answer with explanation:
Presume that, initial water level to be, 0 mm, at a time t=0.
And water level is rising at the rate of .
After 6.2 years level of water will be =1.8 × 6.2
=11.16 mm
→Averge, that is increase in water level after 6.2 years is given by
→→Rate of Depreciating of water level is given by = Negative of Increase of water level=