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sveticcg [70]
2 years ago
8

Ravi buys lunch at a restaurant.

Mathematics
1 answer:
ipn [44]2 years ago
5 0

The price of Ravi's lunch, before tax and tip was added to the total cost of the meal is $13.19.

<h3>What is the price of the lunch?</h3>

Both the tax and the tip paid would increase the cost of the meal. Thus, their dollar value has to be subtracted from the total amount he pays.

Value of the lunch after the tip has been removed = (1 - 0.2) x 17.92 = $14.34

Value of the lunch after the tax has been removed = (1 - 0.08) x $14.34 = $13.19

To learn more about taxes, please check: brainly.com/question/25311567

#SPJ1

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Find the measures of the missing angles
Oliga [24]

Answer:

Step-by-step explanation:

∠1 = 180° - 88° = 92°

∠5 = 81° (alternate interior angles)

∠4 = 180° - ( 81° + 64° ) = 35°

∠3 = 180° - ( 81° + 35° ) = 64°

∠2 = 88° - 64° = 24°

4 0
2 years ago
Read 2 more answers
Easy 5+5+5+5+5+5+555<br><br> this is soo easy<br> answer this for brainiest<br> 2+2+2+22+2+2+22
amm1812

Answer:

585 and 54

Step-by-step explanation:

4 0
2 years ago
What is the solution to the following system?
leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]

Now I will shift rows to make my pivot point (top left) a 1 and so:

\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]

\frac{R_2}{9}=R_2


\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]


4R2+R1=R1 , -14R2+R3=R3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]


-\frac{9}{20}R_3=R_3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]


-\frac{4}{9}R_3+R_2=R2 , -\frac{7}{9}R_3+R_1=R_1


\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]


Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to".  Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0
3 years ago
Working as an insurance salesperson, Ilya earns a base salary and a commission on each new policy, so Ilya’s weekly income, II,
Morgarella [4.7K]

Answer:

l(n) = 80n + 520

Step-by-step explanation:

From the information given in the  question, there is a relationship between the number of new policy sold, n, and earning, I

           For 3 new policies, he earned $760

           For 5 new policies, he earned $920.

The rate of change of IIya's earning with respect to number of new policy sales is

             m = \frac{dI}{dn}

             m = \frac{920 - 760}{5 - 3}

             m = $160 / 2 policies

             m = $80 / policy

The linear equation for the relationship is;

             l(n) = mn + b

I(n) is Ilya’s weekly income which is a function of the number of new policies, n

m is the rate of change of I with respect to n

n is the number of new policies,

b is the intial function which is IIya's income when n equals zero

Recall, Ilya earns a commission of $80 for each policy sold during the week. (m = $80 per policy)

                 l(n) = 80n + b

To complete the relationship l, we need to calculate the initial value b.

For 3 new policies, he earned $760,

             760 = 80(3) + b

             760 = 240 + b

             b = 760 - 520

             b = 520

The final equation is l(n) = 80n + 520

From the final equation, we can deduce that Ilya’s weekly salary is $520 and he earns an additional $80 commission for each new policy sold.

6 0
3 years ago
Write to explain how subtracting 4/5 - 3/5 is similar to subtracting 4 -3
kondor19780726 [428]
Subtracting fractions with a common denominator, you subtract only the numerator, which are 4 and 3, and keep the common denominator the same, underneath the fraction. It is just subtracting 4 and 3 and putting them in a fraction, just like 4-3
6 0
3 years ago
Read 2 more answers
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