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Dahasolnce [82]

1 year ago

10

The stem-and-leaf plot shows test scores for students in Math 7. How many students earned more than a 65 on their test? Key 4|5

= 45 A) 58 students B) 28 students C) 60 students D) 65 students

1 answer:

Nadya [2.5K]1 year ago

7 0

the answer is b

Step-by-step explanation:

hope this helps if not let me know have a blessed day

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the amount of mil available per child in a day care centrr is given by the function m(x) =25/x, where x is the number of childre

Lubov Fominskaja [6]

Answer:

0.5 liters of milk are available per child.

Step-by-step explanation:

Amount of milk available per children:

The amount of milk, in liters, available for x children is given by:

$m(x) = \frac{25}{x}$

50 children are present on a day

This means that $x = 50$

How much milk is available per child?

This is m(50). So

$m(50) = \frac{25}{50} = 0.5$

0.5 liters of milk are available per child.

4 0

2 years ago

ANSWER ASAP PLEASE AND SHOW YOUR WORK!!!!

IgorLugansk [536]

Answer:

f(-x)= -f(x) so, the given function $f(x)= x^3-2x$ is Odd

Step-by-step explanation:

We need to determine if the function $f(x)= x^3-2x$ is Even, Odd, or Neither.

Determining if a function f(x) is even or not we put x=-x and check

If f(-x)=f(x) the function is even

if f(-x)= -f(x) the function is odd

So, Putting x =-x and determining if the given function $f(x)= x^3-2x$ is Even, Odd, or Neither.

$f(x)= x^3-2x\\Put \ x=-x\\f(-x)=(-x)^3-2(-x)\\f(-x)=-x^3+2x\\f(-x)=-(x^3-2x)\\f(-x)=-f(x)$

As f(-x)= -f(x) so, the given function $f(x)= x^3-2x$ is Odd

5 0

2 years ago

To determine how a city's residents feel about building a new youth center, a group considers surveying 50 random children at a

Novay_Z [31]

Answer:

This would most probably result in biased sample since only a specific part of the community is being surveyed that does not represent all of the community.

Step-by-step explanation:

A survey is being conducted to determine how a city's residents feel about building a new youth center.

They are considering to survey 50 random children at a local elementary school.

This would most probably result in biased sample since only a specific part of the community is being surveyed that does not represent all of the community.

Moreover, it is likely that the students of elementary school might not even have any interest in youth center so results would be biased.

Therefore, it is suggested to include a variety of samples that is surveying different age groups that covers all of the community.

8 0

3 years ago

Read 2 more answers

The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec

elena-14-01-66 [18.8K]

If $S(t)$ is the amount of strontium-90 present in the area in year $t$ , and it decays at a rate of 2.5% per year, then

$S(t+1)=(1-0.025)S(t)=0.975S(t)$

Let $S(0)=s$ be the starting amount immediately after the nuclear reactor explodes. Then

$S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)$

or simply

$S(t)=0.975^ts$

So that after 50 years, the amount of strontium-90 that remains is approximately

$S(50)=0.975^{50}s\approx0.282s$

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

$S(t)=se^{kt}$

where $t$ is measured in years. We're told that 2.5% of the starting amount $s$ decays after 1 year, so that

$0.975s=se^k\implies k=\ln0.975$

Then after 50 years, we have

$S(50)=se^{50k}\approx0.282s$

5 0

3 years ago

I NEED HELP I WILL MARK YOU BRAINLIST

natta225 [31]

Answer:

B. -2 1/2 +3 1/4 = 3/4

Step-by-step explanation:

the starting point is -2 1/2, they added 3 1/4, and the ending point is 3/4.

6 0

3 years ago