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Leona [35]
3 years ago
13

Use the graph below. Explain why the intervals on the horizontal axis could make the graph misleading

Mathematics
2 answers:
Nikitich [7]3 years ago
8 0

Answer: A: the intervals are not comparable. The shorter bar spans more than 10 years

Step-by-step explanation:

edge 2021

borishaifa [10]3 years ago
5 0

Answer:

(D) I think

Step-by-step explanation:

Lets look at our answer choices; A.

The intervals are not comparable. The shorter bar spans more than 10 years. When it comes to a horizontal axis it doesn't matter how far it expands,just if it's expanded correctly.

B.The intervals are appropriately labeled. There not it goes from 25 to 50 in just in instant few climbs up.

C.The intervals are not comparable, but the data on the graph is not misleading. It is misleading the graphs are incorrectly labeled.

Which brings us to our answer D.The vertical axis does not have an appropriate scale. it goes from 0-25 25-50 and 50-75 then 75-100. that's a short distance for such numbers that are pretty far apart.

I hope I'm right and I hope this helps:)!

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Given h(x)=-x+5, solve for x when h(x)=3. PLEASE I NEED HELP ILL GIVE BRAINLIEST.
Mice21 [21]

\text{Given that,}\\\\h(x) = -x+5\\\\\implies 3 = -x +5\\\\\implies x = 5 -3 =2

5 0
3 years ago
Someone, please help i don't understand this
miv72 [106K]

Answer

62

5.3

65

5.8

2.5

Step-by-step explanation:

FOr the first one we have the opposite and adjacent side, so we'll use TOA

let x= angle

tan(x)=4.7/2.5

x=61.99 or 62

2.) for this one we can just use pathagoryeous thereom

2.5²+4.7²=c²

28.34=c²

c=5.323

3.) For this one we know that the angles in a traingle must add to 180

let x= missing angle

25+90+x=180

x=65

4.) For this one we have the adjacent side but need the hypotonouse

we will therefore use CAH

cos(25)=5.3/x

5.3/(cos(25))=x

x=5.8

5.) For this one we will just use the pathagoryeous to solve for the missing side

a²+5.3²=5.8²

a²=6.107

a=2.5

8 0
3 years ago
The Answer please!!!!!!!!!!
levacccp [35]

The number of seeds in 2 ounce package is 6.7 × 10⁷ seeds

<h3>Calculating quantity </h3>

From the question, we are to determine the number of seeds in 2 ounce package

From the given information,

An orchid seed weighs 3.2 × 10⁻⁸ ounces

If an orchid seed weighs 3.2 × 10⁻⁸ ounces

Then,

2 ounce package will contain \frac{2}{3\times 10^{-8} } seeds

= 0.67 × 10⁸

= 6.7 × 10⁷ seeds

Hence, the number of seeds in 2 ounce package is 6.7 × 10⁷ seeds

Learn more on Calculating quantity here: brainly.com/question/11262670

#SPJ1

6 0
3 years ago
For the question below, identify the population parameter of interest and the sample statistic we might use to estimate the para
kykrilka [37]

Answer:

Please see the attached file for the complete answer.

Step-by-step explanation:

Download pdf
6 0
4 years ago
Can someone please help me ..I can’t get anymore questions wrong or else I will fail I need help
dedylja [7]

Answer:

maybe number 2

Step-by-step explanation:

because if 2+k=18 then there is no other k there and where did the additional 2 come from ?and 2k=18 then value of k is 9 + there is balance.I may be wrong correct me but i think it is no.2

5 0
3 years ago
Read 2 more answers
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