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dedylja [7]
2 years ago
8

Annabelle owns a small business selling clothing. She knows that in the last week 56 customers paid cash, 26 customers used a de

bit card, and 9 customers used a credit card.
Based on these results, express the probability that the next customer will pay with a debit card as a percent to the nearest whole number.
Mathematics
1 answer:
frosja888 [35]2 years ago
5 0

Answer

23/51

Step-by-step explanation:

The probability of the next customer paying with a debit or credit card is =23/51

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The National Assessment of Educational Progress (NAEP) gave a test of basic arithmetic and the ability to apply it in everyday l
mylen [45]

Answer:

a) 2.0702

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Step-by-step explanation:

Given:

Sample, n = 840

standard deviation, σ = 60

a) The standard deviation of the sampling distribution, will be:

= \frac{\sigma}{\sqrt{n}}

= \frac{60}{\sqrt{840}}

= 2.0702

Standard deviation of the sampling distribution is 2.0702

b) According to the 68 part of the 68-95-99.7 rule, 68% of all values of x fall within 1 standard deviation on either side of the unknown mean μ.

Therefore, missing number will be:

1 * [\frac{\sigma}{\sqrt{n}}]

= 1 * 2.0702

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3 years ago
Find how long it takes for $500 to double if it is invested at 6% interest compounded monthly
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11.581 years

Step-by-step explanation:

Formula:

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6 0
3 years ago
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
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