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Tasya [4]
2 years ago
14

Help me please i need it done 20 points

Mathematics
1 answer:
alekssr [168]2 years ago
7 0
\bold{ANSWER:}
x ≈ 41.5

\bold{SOLUTION:}

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A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
3 years ago
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Vanessa reads door books in seven weeks. How many books did she read each week?
stiks02 [169]
49 books u gotta multiply 7 days times 7 weeks
4 0
3 years ago
If n = 37 cm and l = 12 cm, what is the length of m?
emmainna [20.7K]

<em> would say that the answer is </em><em>A. 25 cm</em><em> only because 37-12=25 and I don't necessarily know what the question is trying to ask.</em>

<em>Hope this Helps!<3</em>

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4 years ago
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What Greek mathematician is known as the father of Geometry?
Luden [163]
C. Euclid is known as the father of Geometry

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3 years ago
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Point f lies between points g and m. gf =12x+4, fm=16 and gm =16x what is the value of x
Flura [38]

\underset{\leftarrow \qquad \text{\LARGE 16x}\qquad \to }{\stackrel{12x + 4}{G\rule[0.35em]{10em}{0.25pt}} F\stackrel{16}{\rule[0.35em]{16em}{0.25pt}M}} \\\\\\ \stackrel{GF}{12x+4} ~~ + ~~ \stackrel{FM}{16} ~~ = ~~ \stackrel{GM }{16x}\qquad \implies 12x+20=16x \\\\\\ 20=4x\implies \cfrac{20}{4}=x\implies 5=x

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2 years ago
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