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almond37 [142]
3 years ago
6

If cos 67 degrees is close to 2/5 which is closest to the length of no

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

40 cm

Step-by-step explanation:

In the right triangle PNO:

  • ∠N = 90°
  • PO = 100cm  (the hypotenuse of the triangle)
  • ∠P = 23°
  • ∠O = 90° - 23° = 67°
  • side NO is adjacent to ∠O

By definition:

cos(β) = adjacent/hypotenuse

Replacing with data and solving for NO:

cos(∠O) = NO/PO

2/5 = NO/100

NO = (2/5)*100

NO = 40

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