Write the fractional equivalent (in reduced form) to each number 30 points

Mathematics

1 answer:

tankabanditka [31]4 years ago

7 0

Correct answers are:

1)    1/3 (NOT 3/10). .3 repeating is not 3/10, 3/10 is .3.
2)    1/8. To solve, .125 has three places, so use 1000. 1000/125 is 8, that is your denominator. 125/125 is 1 is your numerator.
3)    1/6 (divide 100/16, which is 6 ¼ - round to 6. If you carry this out to 1,000,000/166,667, it is very close to 6.
4)    1/10
5)    2/3 (NOT 3/5)
6)    1/5 (2/10 reduced to 1/5)
7)    3/4 (75/100 reduced)

<span />

You might be interested in

Use mental math to solve the equation. x – 14 = 13

Ahat [919]

X=27 because you would add 14 to 13

6 0

3 years ago

An equation of a hyperbola is given.

siniylev [52]

Answer:

The vertices are $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

The foci are $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$ .

The asymptotes are $y=2x,\:y=-2x$ .

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

$\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1$ is the standard equation for a right-left facing hyperbola with center $\left(h,\:k\right)$ .

The vertices $\:\left(h+a,\:k\right),\:\left(h-a,\:k\right)$ are the two bending points of the hyperbola with center $\:\left(h,\:k\right)$ and semi-axis a, b.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and vertices $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

For a right-left facing hyperbola, the Foci (focus points) are defined as $\left(h+c,\:k\right),\:\left(h-c,\:k\right)$ where $c=\sqrt{a^2+b^2}$ is the distance from the center $\left(h,\:k\right)$ to a focus.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ $c=\sqrt{3^2+6^2}= 3\sqrt{5}$ and foci $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$

The asymptotes are the lines the hyperbola tends to at $\pm \infty$ . For right-left hyperbola the asymptotes are: $y=\pm \frac{b}{a}\left(x-h\right)+k$