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Yuri [45]
2 years ago
11

Beyonce and Jay Z want Blue Ivy to have a sibling. However, Beyonce is worried because Jay Z has a unibrow (a dominant trait). S

he doesn’t want her children to have the same attached eyebrows. Beyonce is recessive for unattached eyebrows.
Biology
1 answer:
weeeeeb [17]2 years ago
4 0

The trait that is dominant or reccessive can be obtained by the use of a Punnet square or by the use of the conventional crossing of allele pairs.

<h3>What are traits?</h3>

The term traits refers to the expressed characteristics of an organism. The dominant trait is expressed while the reccessive trait is not expressed.

The trait that is dominant or reccessive can be obtained by the use of a Punnet square or by the use of the conventional crossing of allele pairs.

Learn more about traits:brainly.com/question/7602134

#SPJ1

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Answer:

That is false.

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Which one type of analytics would be used to analyze hospital readmission rates for heart failure?
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A broad, flat muscle of lower back<br> a. Adductor magnus<br> b. Latissimus dorsi
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3 years ago
What is the Hardy Weinberg formula?
natulia [17]
 p2<span> + 2pq + q</span>2<span> = 1. is the equation</span>
4 0
3 years ago
Read 2 more answers
. In this example, red flower coloring is dominant to white, and your population of 200 plants has 150 plants with red flowers.
AnnyKZ [126]

Answer:

a) The allele frequencies are - p= 0.8660\\q= 0.134

b) Genotype frequencies for this population- p^2=0.75, q^2= 0.0179, 2pq = 0.2321

Explanation:

Given ,

Red color of flower is dominant to white color flower

Let "R" represents allele for red color and "r" represents allele for white color

out of 200 flower, 150 are red flowers.

So the frequency of red flowers with genotype "RR" is equal to

p^{2} = \frac{150}{200} \\p^{2} =0.75

As per hardy Weinberg's I equilibrium equation -

p+q=1\\p=\sqrt{p^2} \\p=\sqrt{0.75} \\p= 0.8660\\q= 1-p\\q= 1-0.8660\\q = 0.134

a) The allele frequencies are - p= 0.8660\\q= 0.134

Frequency of genotype "rr" i.e homozygous recessive white flower is

q^{2} \\0.134^2\\q^2 = 0.0179\\

Substituting the values of p^2 and q^2, in below equation, we get -

p^2+2pq+q^2=1\\2pq= 1-p^2-q^2\\2pq= 1-0.75-0.0179\\2pq=0.2321

b) Genotype frequencies for this population- p^2=0.75, q^2= 0.0179, 2pq = 0.2321

8 0
3 years ago
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