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2 years ago

Samuel is trying to construct the inscribed circle of a triangle.

Mathematics

1 answer:

Yuki888 [10]2 years ago

3 0

The next step to complete the construction will connect the in-center to one of the sides of the triangle.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

Samuel is trying to construct the inscribed circle of a triangle.

Using the angle bisectors to find the in-center.

Where two angles bisector meets, the point called in-center.

Next step will be: connect the in-center to one of the sides of the triangle.

Thus, the next step to complete the construction will be connect the in-center to one of the sides of the triangle.

Learn more about circle here:

brainly.com/question/11833983

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Richard cuts a piece of wood for a project. The first cut is shown and can be represented by the equation y = 1/2x + 2. The Seco

Morgarella [4.7K]

Since it is parallel, gradient must be the same so it will be 1/2
y=1/2x+c
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equation is y=1/2x-7

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3 years ago

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Three streets intersect to form a right triangle as shown below. The parts of streets that make up the legs of this triangle are

Burka [1]

Answer:

70 yd.

Step-by-step explanation:

The three streets at the intersection form a right triangle.

For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:

$h=\sqrt{x^2+y^2}$

where

x is the length of the 1st side

y is the length of the 2nd side

h is the length of the hypothenuse

Here we want to find the hypothenuse.

We have:

x = 42 yd (length of the 1st side)

y = 56 yd (length of the 2nd side)

Substituting, we find h:

$h=\sqrt{42^2+56^2}=70 yd$

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3 years ago

Three times the sum of a number and 4 is twice a number minus 8.

amm1812

Answer:

Step-by-step explanation:

3(n+4)=2n-8

3n+12=2n-8

5n= -20

n= -4

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3 years ago

I need a step by step instruction please

Alika [10]

Answer: $x=52$

Step-by-step explanation:

$x-45+45=7+45\\x=52$

3 0

2 years ago

A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

5 0

3 years ago