I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Divide both sides by the numeric factor on the left side then solve x=9
Answer: See explanation
Step-by-step explanation:
Since we given the information that Jordan is preparing serving of baby carrots and that he has 96 baby carrots, while each serving is 12 carats.
The number of shearings that Jordan can prepare will be:
= 96 / 12
= 8
From the above calculation, there won't be any carrots left since we do not have a remainder.
Answer:
54.87
69.08
Step-by-step explanation:
Answer:
i think its B
Step-by-step explanation:
