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4 years ago

Will give BRAINLIEST

Mathematics

2 answers:

Lerok [7]4 years ago

4 0

Answer:

x = 20°

Step-by-step explanation:

Given

3x + 80° + 2x = 180° [ being linear pair ]

5x + 80° = 180°

5x = 180° - 80°

5x = 100°

x = 100° / 5

Therefore x = 20°

Hope it will help. :)

Kisachek [45]4 years ago

3 0

Answer:

x=20

Step-by-step explanation:

The angles are all on a straight line, therefore they are supplementary. This means they add to 180 degrees.

So,

3x+80+2x=180

Combine like terms

(3x+2x)+80=180

5x+80=180

Subtract 80 from both sides

5x+80-80=180-80

5x=100

Divide both sides by 5

5x/5=100/5

x=20

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What is the sum of the expressions for n=-2n=−2 and m=5m=5 ?

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Answer:

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Step-by-step explanation:

Expression: (3m+2n−6) and (−4−6m+7n)

n= -2 and m=5

Before inserting the values, let's add both expressions.

(3m+2n−6) + (−4−6m+7n)

3m+2n−6 −4 − 6m + 7n

-3m + 9n - 10

Inserting the values;

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6 0

3 years ago

Pls I'm really confused

aniked [119]

Would it be 3x times as far and the second answer 2x as far

8 0

3 years ago

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m

Flauer [41]

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

semiperimeter: p = (51+37+20):2 = 54 m

Area of triangle:

$A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2$

Rate: ₹ 3 per m².

Cost: ₹ 3•306 = ₹ 918

2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm

p = 11:2 = 5.5

$A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2$

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

p = (8•3):2 = 12 cm

$A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2$

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

b = 3x

2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm

p = 32:2 = 16 cm

$A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2$