(y-14)=8/2
y-14=4
y=4+14
y=18
I just graphed the table next to the graph of g and compared the two.
The y-intercept of f is (0,8) and the y-intercept of g is (0, -2). So f is GREATER THAN the y-intercept of g.
Now to do the average rate of change, I see from the interval [-6,-3] that f is decreasing and for g it is increasing. Thus f is LESS THAN the average rate of change of g.
The value of x = 0 which is none
