By definition we have the following equation:
t = d / v
Where,
t: time
d: distance
v: speed
For this case we have:
d / 30 + d / 4 = 17
Rewriting we have:
2d + 15d = 17 (60)
17d = 17 (60)
d = 60 mi
Then, the walking time is
t = d / v
t = 60/4
t = 15 hours
Answer:
She walked
t = 15 hours
<u>Given</u>:
The given equation is 
We need to determine the approximate value of q.
<u>Value of q:</u>
To determine the value of q, let us solve the equation for q.
Hence, Subtracting
on both sides of the equation, we get;

Subtracting both sides of the equation by 2q, we have;

Dividing both sides of the equation by -1, we have;

Now, substituting the value of
, we have;

Subtracting the values, we get;

Thus, the approximate value of q is 0.585
Hence, Option C is the correct answer.
Answer:
Check the explanation
Step-by-step explanation:
kindly check the attached image below to Determine whether the given set S is a subspace of the vector space <u><em>(which is contained within a different vector space. So all the subspace is a kind of vector space in their own way, although it is also defined relative to some of the other larger vector space. The linear subspace is more often than not simply called a subspace whenever the situation serves to differentiate it from other types of subspaces.)</em></u> V.A
<span>2<span>x2</span>+xy+2<span>y2</span>=5</span>Implicit differentiation yields<span>4x+y+x<span>y′</span>+4y <span>y′</span>=0</span>Solve for <span>y′</span><span>.
answer is- y = 4x+ y /5x</span>