CAN SOMEONE HELP PLZ ASAP!

Mathematics

1 answer:

Anna35 [415]3 years ago

8 0

Answer:

A= 1/8
B= 3/8

Solution:
Count how many lines there are except the Line on zero. This number is 8 and will be the denominator. Then count the number of lines to the one you’re looking at

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The____of an angle is the ratio of the opposite leg length to the adjacent leg length.

Helen [10]

Tangent, the acronym SOH-CAH-TOA can help, SOH= sine over hypotenuse, CAH= cosine over hypotenuse, and TOA= opposite over adjacent

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Joey had 40 words to study for a spelling quiz, but he only learned 10 of them. His teacher surprised the class by telling them

Natasha2012 [34]

Answer:

The probability of choosing a word randomly which is one of the words Joey learned = 1/4

Step-by-step explanation:

Total number of words to be memorized = 40 words

The number of words memorized by Joey = 10

Let E: Event of randomly choosing a word that Joey has learned.

P(E) = $\frac{\textrm{The total words learned by Joey}}{\textrm{Total Words in the quiz}}$

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Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation

Leto [7]

Answer:

There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, so $\mu = 47.88, \sigma = 3.09$