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2 years ago

I'm in desperate need of help <\3

Mathematics

1 answer:

denis-greek [22]2 years ago

6 0

Answer:

8 Answer is a) R

And

9 Answer is b) -4

Answer of your Question bro and good evening and I hope this will help you and please mark me as brainliest and thank u have a amazing day

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Ilya [14]

Answer:

There are three measures of center (most used) for a data set:

mean
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3 years ago

Read 2 more answers

Ming took a cab across town. His fare was $22, and he leaves an 18% tip. What is the total amount ming pays the cab driver.

Aleks04 [339]

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{18\% of 22}}{\left( \cfrac{18}{100} \right)22}\implies 3.96~\hfill \stackrel{\textit{total amount paid}}{22+3.96\implies 25.96}\\\hspace{34em}$

8 0

3 years ago

SMILEYYOFFICAL SERIOUSLY WHATS 6x^2 \ by 45x

densk [106]

6x^2 / 45x = 6x / 45
6x / 45 = 2x / 15

5 0

4 years ago

What number is 10% of 5

harina [27]

You just need to divide 5 by 10
5 divided by 10 = 0.5

6 0

3 years ago

In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s

MaRussiya [10]

Answer:

The mentioned number in the exercise is:

362

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

x = hundredths digit
y = tens digit
z = ones digit

We can write:

x = z + 1 (the hundreds digit is one more than the ones digit).
y = 2x (the tens digit is twice the hundreds digit).
x + y + z = 11 (the sum of the digits is 11).

Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

x + y + z = 11
(z + 1) + y + z = 11 (remember x = z + 1)
z + 1 + y + z = 11
z + z +y + 1 = 11 (we just ordered the equation)
2z + y + 1 = 11 (z + z = 2z)
2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
2z + y = 10
2z + (2x) = 10 (remember y = 2x)
2z + 2x = 10
2z + 2(z + 1) = 10 (x = z + 1 again)
2z + 2z + 2 = 10
4z + 2 = 10
4z = 10 - 2
4z = 8
z = 8/4
z = 2

Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:

x = z + 1
x = 2 + 1
x = 3

And we'll use the second equation to obtain the value of y (the tens digit):

y = 2x
y = 2(3)
y = 6

Organizing the digits, we obtain the number:

Number = xyz
Number = 362

As you can see, the obtained number is 362.

8 0

3 years ago