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3 years ago

What is the following sum? 5(3√x)+9(3√x)

Mathematics

2 answers:

Liula [17]3 years ago

4 0

Answer:

Option (c) is correct.

$5(\sqrt[3]{x})+9(\sqrt[3]{x} )=14\sqrt[3]{x}$

Step-by-step explanation:

Given : expression $5(\sqrt[3]{x})+9(\sqrt[3]{x} )$

We have to choose the correct option from the given options to the sum of the given expression.

Consider the given expression $5(\sqrt[3]{x})+9(\sqrt[3]{x} )$

Taking $\sqrt[3]{x}$ common from both terms, we have,

$(\sqrt[3]{x})(5+9)=14\sqrt[3]{x}$

Thus, $5(\sqrt[3]{x})+9(\sqrt[3]{x} )=14\sqrt[3]{x}$

charle [14.2K]3 years ago

3 0

5(3√x)+9(3√x)
=3√x(5+9)
=14(3√x)

answer is C. third choice 14(3√x)

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Identify whether each phrase is an expression, equation, or inequality.<br> Term Phrase

Llana [10]

The first Phrase

$0=p-\frac{7}{3}$ , is a equation.

The second phrase

4q>s+ $6^{4}$ , is an inequality.

The third phrase

4a-5 is an expression

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The first Phrase

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A equation contain operand, operators(+,-,*,/) and an equal sign.

The second phrase

4q>s+ $6^{4}$ , is an inequality.

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4a-5 is an expression

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6 0

2 years ago

Inga divided two identical rectangles into equal parts. She colored one part of each rectangle.

likoan [24]

Answer:

The areas are equal.

Step-by-step explanation:

Let the first rectangle be R and

the second rectangle be R'.

Sine R and R' are identical, their lengths are equal and their breadths are equal.

So, if Inga divided each into equal parts, then each part of both rectangles are equal.

Hence, the colored parts of both rectangles are equal.

8 0

2 years ago

In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa

MakcuM [25]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

Step-by-step explanation:

Data given and notation

$X_{1}=25$ represent the number of homeowners who would buy the security system

$X_{2}=9$ represent the number of renters who would buy the security system

$n_{1}=140$ sample 1

$n_{2}=60$ sample 2

$p_{1}=\frac{25}{140}=0.179$ represent the proportion of homeowners who would buy the security system

$p_{2}=\frac{9}{60}= 0.15$ represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a two sided test the p value would be:

$p_v =2*P(Z>0.500)=0.617$

6 0

3 years ago

Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha

Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

$a = 20$ --- tree distance from north gate

$b =14$ --- movement from south gate

$c = 1775$ --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

$\triangle ADE \sim \triangle ACB$ --- similar triangles

So, we have the following equivalent ratios

$AE:DE = AB:CB$

Where:

$AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775$

Substitute these in the above equation

$20:x/2 = 20 + x + 14: 1775$

$20:x/2 = x + 34: 1775$

Express as fraction

$\frac{20}{x/2} = \frac{x + 34}{1775}$

$\frac{40}{x} = \frac{x + 34}{1775}$

Cross multiply

$x *(x + 34) = 1775 * 40$

Open bracket

$x^2 + 34x = 71000$

Rewrite as:

$x^2 + 34x - 71000 = 0$

Expand

$x^2 + 284x -250x - 71000 = 0$

Factorize

$x(x + 284) -250(x + 284)= 0$

Factor out x + 284

$(x - 250)(x + 284)= 0$

Split

$x - 250 = 0 \ or\ x + 284= 0$

Solve for x

$x = 250 \ or\ x =- 284$

x can't be negative;

So:

$x = 250$

6 0

3 years ago

Please! Help thank you

LUCKY_DIMON [66]

Answer:

i dont know sorry

Step-by-step explanation:

5 0

2 years ago