Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost

Question

2 years ago

6

$15. For one performance, there were 65 tickets sold in all, and the total amount paid for them was $1500 . How many tickets of each type were sold?

1 answer:

Tju [1.3M] · Answer 1 · 2023-01-12T10:10:31+03:00

The advance tickets were 35 in number and the same day ticket will be 30 in number.

<h3>What will be the number of tickets?</h3>

To find out the number of the tickets sold we will give some notations so the notations are as follows:-

A= Cost of advance tickets=$30

S= cost of same-day ticket-=15

$N_A=$ Number of the advance tickets

$N_S=$ Number of same-day tickets.

The equations made by the given data will be:-

$30N_A+15N_S=1500\\\\\\N_A+N_S=65$

By solving the above equations:-

$N_S=30\ \ \ \ \ \ N_A=35$

Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.

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