Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost $15. For one performance, there were 65 tickets sold in all, and the total amount paid for them was $1500 . How many tickets of each type were sold?

Answer 1

The advance tickets were 35 in number and the same day ticket will be 30 in number.

What will be the number of tickets?

To find out the number of the tickets sold we will give some notations so the notations are as follows:-

A= Cost of advance tickets=$30

S= cost of same-day ticket-=15

$N_A=$ Number of the advance tickets

$N_S=$Number of same-day tickets.

The equations made by the given data will be:-

$30N_A+15N_S=1500\\\\\\N_A+N_S=65$

By solving the above equations:-

$N_S=30\ \ \ \ \ \ N_A=35$

Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.

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