1. Round 50.75 to 50 and 0.18 to 0.20.
50 x 0.2 = 10
2) Round 96 to 100 and 0.499 to 0.5
100 divided by 0.5 = 50
3a) Round 8.2 to 8, 6.7 to 7, and 0.46 to 0.50
8 x 7 divided by 0.50 = 112
3b) Round 23.4 to 20, 13.9 to 10, and 0.18 to 0.20
20 x 10 divided by 0.20 = 2,000
Hi there
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 100
R interest rate 0.02
K compounded monthly 12
T time?
We need to solve for t
T=[log (A/p)÷log (1+r/k)]÷k
T=(log(3,000÷100)÷log(1+0.02÷12))÷12
T=170.202 years
So it's a
Hope it helps
Answer:
1,2, and 4
Step-by-step explanation:
I attached a picture with the graph
y= -4 is a straight horizontal line (red line) and
y≤10 will give a horizontal line passing trough y=10 (blue line)
the solution is all points under and on the line y=10
1, 2, and 4 are part of the solution set
(the blue area is the solution of the system of equations)
Answer:
Step-by-step explanation:
<u>Common Factors</u>
An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.
The following expression
Can be factored in the constants and in the variable x.
1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).
2. To find the common factors of the constants, we take all the coefficients:
12 - 20 - 32
and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8
3. The factored expression is