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2 years ago

What is the equation of a line that has an x-intercept of 5 and a slope of 4?

Mathematics

1 answer:

dimulka [17.4K]2 years ago

8 0

Answer:

y=4x-20

Explanation:

Since we already have a slope, all we need to do is just find the y-intercept. To do this we can make an XY t-chart.

Using the chart we can see that for every x that decreases, a y decreases 4 times. So if we subtract 5 from x, we will multiply 5 times y. Note that this graph is increasing so the y-intercept is negative. -5 · 4 = -20

X | Y

6 | 4

5 | 0

0 | -20

Hope this Helps!

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What is the greatest common factors of 60w,34w^2,and 24w^4

andrew11 [14]

Answer: 2w

Step-by-step explanation:

The greatest common factor could also be referred to as the Highest common factor. Now

60w, 34w² and 24w⁴

Now let concert each to its factors

60 = 2 × 2 × 3 × 5 × w

34w² = 2 × 17 × w × w

24w⁴ = 2 × 2 × 2 × 3 × w × w × w × w

Therefore H.C.F or the greatest common factor

G.C.F = 2 × w

= 2w

4 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

Help please

Nikitich [7]

Answer:

35 bagels

Step-by-step explanation:

Duh

8 0

3 years ago

A rectangular prism has a length of 3/8 a width of 5/8 and height of 7/8, what is the volume

Allisa [31]

L x w x h
3/8=0.375
5/8=0.625
7/8=0.875
0.375x0.625x0.875 =
0.205078125.......... doesn't seem right but that's what i got

6 0

3 years ago

Help please someone please

suter [353]

Answer:

C' will be located at (-4,-2)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers