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LenKa [72]
2 years ago
13

What is 3/4+.06? Please help I would really appreciate it thanks!

Mathematics
2 answers:
Greeley [361]2 years ago
6 0
If you convert the fraction to a decimal then it would be .75 and then if you added the .06 to the equation then your final answer would be 0.81. I hope this helps.
e-lub [12.9K]2 years ago
4 0
3/4 =0.75
0.75+0.06=0.81
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Help! It says that I need to determine If both equations represent lines which are parallel, perpendicular, or none...
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    4x + 2y = 8     (1)
    8x + 4y = -4y  (2)

A) Two lines are parallel if they have the same gradient
       - putting both equations into the gradient- intercept form ( y = mx + c                where m is the gradient)
            (1) 4x + 2y = 8
                          2y = 8 - 4x
                            y = -2x + 4
             
            (2) 8x + 4y = -4y
      <span>                    </span>8x = -4y - 4y
                            y = \frac{-8x}{-8}
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   <span>Thus the gradient of the two equations are different and as such          the two lines are not parallel
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B)  When two lines are perpendicular, the product of their gradient is -1
                   m_{1} * m_{2} = p
                                             p = (-2) * (-1)
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<span>          ∴ the two lines are not perpendicular either.</span>

Thus these lines are SKEWED LINES

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2 years ago
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What is 437284237940 divided by 2 - 2 times 1 -3 +42 divided by 7989
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6 0
3 years ago
On the grid, sketch a graph to represent
Greeley [361]

Answer:

Please find attached, the required graph created on MS Excel

Step-by-step explanation:

The distance between Sandy's house and the school = 200 m

The number of minutes Sandy talked to her friend for = 10 minutes

The time it took Sandy to return home to pick her homework = 5 minutes

Let <em>x </em>represent Sandy's location she stops to talk to her friend 10 minutes, we have;

The slope of the motion on the graph, m₁ = (x - 0)/(t - 0)

The slope of her motion running home to pick the up her homework, m₂ = (x - 0)/(5 - 0)

Given that t > 5, the slope on trip back home, m₁, is larger than are her initial slope, m₂

Therefore, where x = 125, we have;

The rate at which she returned home = m₂ = (125 m - 0)/(5 min - 0) = 25 m/min

Given that the same rate m₂ is what she used in heading back to school, we have;

The time it takes her to get to school = 200 m/(25 m/min) = 8 minutes

Therefore, whereby it took her 10 minutes to reach point <em>x</em>, we have the following coordinate points on the graph in a tabular form;

\begin{array}{ccc} Time \ (minutes) \ x-axis&&Distance  \ (meters) \ y-axis\\0&&0\\10&&25\\15&&0\\23&&200\end{array}

The plot of the above point is completed using MS Excel as shown in the attached diagram.

7 0
2 years ago
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