Question

Write y=x^2-6x+17 in vertex form. step by step

Answer 1

Step-by-step explanation:

the general vertex form is

y = a(x - h)² + k

with (h, k) being the vertex.

after doing all the multiplications we get

y = a(x² - 2hx + h²) + k = ax² - 2ahx + ah² + k

our original equation is

y = x² - 6x + 17

and now we simply compare the cording parts :

ax² = x²

a = 1

-2ahx = -2hx = -6x

-2h = -6

h = -6/-2 = 3

ah² + k = 17

3² + k = 17

9 + k = 17

k = 8

so the vertex form is

y = (x - 3)² + 8