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noname [10]
4 years ago
10

What is the zero of r(x)=8/3x-16

Mathematics
2 answers:
Art [367]4 years ago
4 0
I think the answer is zero

I hope this helps
MissTica4 years ago
4 0
Is this trigonometry
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A pizzeria charges $8 for a large cheese pizza, plus $2 for each topping. The total cost for a large pizza is given by the equat
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Lines l and m are perpendicular. if the slope of line m is -4/3, what is the slope of line l?
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the slope of line L must be 3/4
8 0
4 years ago
Reducing fractions 5 to 30.
Crazy boy [7]

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5 \leqslant x \leqslant  30

4 0
3 years ago
The Wall Street Journal reported that the age at first startup for 90% of entrepreneurs was 29 years of age or less and the age
Hitman42 [59]

Answer:

(a) \hat p\sim N(0.90,\ 0.0212^{2}})

(b) \hat q\sim N(0.10,\ 0.0212^{2}})

(c) Not different.

Step-by-step explanation:

The information provided is:

  • The age at first startup for 90% of entrepreneurs was 29 years of age or less.
  • The age at first startup for 10% of entrepreneurs was 30 years of age or more.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

Let <em>p</em> represent the proportion of entrepreneurs whose first startup was at 29 years of age or less.

A sample of <em>n</em> = 200 entrepreneurs is selected.

As <em>n</em> = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

\mu_{\hat p}=p=0.90\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.90(1-0.90)}{200}}=0.0212

So, \hat p\sim N(0.90,\ 0.0212^{2}}).

(b)

Let <em>q</em> represent the proportion of entrepreneurs whose first startup was at 30 years of age or more.

A sample of <em>n</em> = 200 entrepreneurs is selected.

As <em>n</em> = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

\mu_{\hat q}=q=0.10\\\\\sigma_{\hat q}=\sqrt{\frac{q(1-q)}{n}}=\sqrt{\frac{0.10(1-0.10)}{200}}=0.0212

So, \hat q\sim N(0.10,\ 0.0212^{2}}).

(c)

The standard deviation of sample proportions is also known as the standard error.

The standard deviation of <em>p</em> is, 0.0212.

The standard deviation of <em>q</em> is, 0.0212.

Thus, the standard errors of the sampling distributions in parts (a) and (b) are same.

5 0
3 years ago
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