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Tatiana [17]
3 years ago
9

Need Help Asap offering 10 Points!!!!

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

13 minutes 30 seconds.

Step-by-step explanation:

You just divide 10.8 by 0.8...

10.8÷0.8=13.5

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Simplify (5 to the power of 1/3) to the power of 3
Sladkaya [172]

Answer:

C

Step-by-step explanation:

Multiply the exponents

Reduce the gcf

Hope ghis helps! :)

6 0
3 years ago
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Clara and Toby are telemarketers. Yesterday, Clara reached 4 people in 10 phone calls, while Toby reached 3 people in 8 phone ca
dangina [55]

I hope this helps you.


4/10 = .4

3/8 = .375

.4 > .375, so Clara will reach more people

Another way to look at it:

4/10 * 40 to 4 * 4 = 16 people reached

3/8 * 40 to 3 * 5 = 15 people reached

5 0
4 years ago
Read 2 more answers
CAN SOMEONE PLS ANSWER-If W(- 10, 4), X(- 3, - 1) , and Y(- 5, 11) classify AEXY by its sides . Show all work to justify your an
AnnZ [28]

Answer:

  • WX = \sqrt{74} \approx 8.6023253\\\\
  • XY = 2\sqrt{37} \approx 12.1655251\\\\
  • WY = \sqrt{74} \approx 8.6023253\\\\
  • Classify:  Isosceles

============================================================

Explanation:

Apply the distance formula to find the length of segment WX

W = (x1,y1) = (-10,4)

X = (x2,y2) = (-3, -1)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-3))^2 + (4-(-1))^2}\\\\d = \sqrt{(-10+3)^2 + (4+1)^2}\\\\d = \sqrt{(-7)^2 + (5)^2}\\\\d = \sqrt{49 + 25}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\

Segment WX is exactly \sqrt{74} units long which approximates to roughly 8.6023253

-------------------

Now let's find the length of segment XY

X = (x1,y1) = (-3, -1)

Y = (x2,y2) = (-5, 11)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-5))^2 + (-1-11)^2}\\\\d = \sqrt{(-3+5)^2 + (-1-11)^2}\\\\d = \sqrt{(2)^2 + (-12)^2}\\\\d = \sqrt{4 + 144}\\\\d = \sqrt{148}\\\\d = \sqrt{4*37}\\\\d = \sqrt{4}*\sqrt{37}\\\\d = 2\sqrt{37}\\\\d \approx 12.1655251\\\\

Segment XY is exactly 2\sqrt{37} units long which approximates to 12.1655251

-------------------

Lastly, let's find the length of segment WY

W = (x1,y1) = (-10,4)

Y = (x2,y2) = (-5, 11)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-5))^2 + (4-11)^2}\\\\d = \sqrt{(-10+5)^2 + (4-11)^2}\\\\d = \sqrt{(-5)^2 + (-7)^2}\\\\d = \sqrt{25 + 49}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\

We see that segment WY is the same length as WX.

Because we have exactly two sides of the same length, this means triangle WXY is isosceles.

8 0
3 years ago
Calculate the surface area of the composite figure
zhannawk [14.2K]

Answer:

Below in bold.

Step-by-step explanation:

Total surface area = 1/2 * area of a sphere + area of the side o a cone

=  1/2 * 4 π r^2 + π r L

= 1/2 * 4 π 7^2 + π*7*25

=  307.876 + 549.779

= 857.65 in^2 to nearest hundredth.

8 0
3 years ago
Estimate the size of a crowd walking in a charity fundraising march that occupies a rectangular space with dimensions of 10 feet
jolli1 [7]

Answer:

4000 is size of a crowd walking in a charity fundraising March.

Step-by-step explanation:

Given:

Dimensions of rectangular space 10 feet by 12000 feet

So we can say that,

Length = 1200 ft

Width = 10 ft

Now we will calculate the area of rectangular space which is given by

Hence Area will be = length\times width= 10\ ft \times 1200 \ ft= 12000 \ ft^2

Now we know that 40 people occupy a rectangle measuring 10 feet by 12 feet.

Length = 12 ft

Width = 10 ft

Area = length\times width= 10\ ft \times 12 \ ft= 120 \ ft^2

It says that 40 people are occupied in 120 ft^2

So how many people will be there in 12000 ft^2

By using unitary method we get,

Number of people = \frac{40\times 12000 \ ft^2}{120 \ ft^2} = 4000 \ peoples

Size of a crowd walking in a charity fundraising March is 4000.

8 0
4 years ago
Read 2 more answers
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