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1 answer:
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<span>deconstructing
48 : 2 = 24
24 : 2 = 12
12 :2 = 6
6 : 2 = 3
3 : 3 = 1
2 * 2 * 2 * 2 * 3 = 48
...................................
16 : 2 = 8
8 : 2 = 4
4 : 2 = 2
2 : 2 = 1
2 * 2* 2 * 2 = 16
..................................
12 : 2 = 6</span>
<span>
6 : 2 = 3
3 : 3 = 1
</span><span>common denominator 48</span>
48 : 2 = 24
24 : 2 = 12
12 :2 = 6
6 : 2 = 3
3 : 3 = 1
2 * 2 * 2 * 2 * 3 = 48
...................................
16 : 2 = 8
8 : 2 = 4
4 : 2 = 2
2 : 2 = 1
2 * 2* 2 * 2 = 16
..................................
12 : 2 = 6</span>
6 : 2 = 3
3 : 3 = 1
</span><span>common denominator 48</span>
Answer:
1. Find the difference between the areas.
<u>Area of the small rectangle</u>:
<u>Area of the big rectangle</u>:
The difference is:
2.
You can solve this question just by looking at the graph.
a) The height is 4 meters.
To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.
The height is 4 meters.
b) 9 meters.
For
b) The ball travels 4 meters.
But to calculate it, it is when
Using the quadratic formula:
It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.
3.
In this question, we have to find the area of the cylinder and the sphere.
From the information given, we have
a = 5mm and d = 5mm, therefore the radius is 2.5 mm.
The volume of a cylinder:
The volume of the sphere:
The volume of the capsule is approximately