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Neporo4naja [7]

3 years ago

15

Are the given lenghts a right triangle? 28, 53,45

2 answers:

stepan [7]3 years ago

7 0

Answer:

not at all

Step-by-step explanation:

this is a scalene triangle cuz each side is a different length.

aalyn [17]3 years ago

5 0

Yes that should be correct

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The formula for the standard deviation of a sample is:

timofeeve [1]

Answer:

d. The variance is 9.56 and the standard deviation is 3.09.

Step-by-step explanation:

From the above question, we are given the following data set.

3, 7, 8, 8, 8, 9, 10, 10, 13, 14

a) Mean = 3 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 13 + 14/ 10

= 90/10

= 9

b) Variance

The formula for sample Variance = (Mean - x)²/ n - 1

Mean = 9

n = 10

Sample Variance =

(3 - 9)² + (7 - 9)² + (8 - 9)² + (8 - 9)² + (8 - 9)² + (9 - 9)² + (10 - 9)² + (10 - 9)² + (13 - 9)² + (14 - 9)² / 10 - 1

= 36 + 4 + 1 + 1 + 1 + 0 + 1 + 1 + 16 + 25/9

= 86/9

= 9.555555556

≈ Approximately 9.56

Variance = 9.56

Sample Standard deviation = √Sample Variance

= √9.56

= 3.0919249667

≈ Approximately 3.09

5 0

3 years ago

Just need the equation

Anna007 [38]

$a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}$

Each of the equations can be solved as shown below:

a. $3x + 7 = - x - 1$

$3x + 7 + x = - x - 1 + x$ (<em>addition property of equality</em>)

$4x + 7 = - 1\\4x + 7 - 7 = -1-7$ (<em>Subtraction property of equality</em>)

$4x = -8\\\frac{4x}{4} = \frac{-8}{4}$ <em> (Division property of equality)</em>

<em /> $x = -2$

b. $1 - 2x + 5 = 4x - 3\\$

<em>Add like terms </em>

<em /> $6 - 2x = 4x - 3\\\\6 - 2x - 6 = 4x - 3 - 6$ (<em>Subtraction property of equality</em>)

$- 2x = 4x - 9\\-2x - 4x = 4x -9 - 4x$ <em> (Subtraction property of equality)</em>

<em /> $-6x = -9 \\\frac{-6x}{-6} = \frac{-9}{-6}$ <em> (Division property of equality)</em>

<em /> $x = \frac{3}{2}$

c. $4x - 2 + x =-2 + 2x\\$

$5x - 2 = -2 + 2x\\5x - 2x = -2 + 2\\3x = 0\\ x = \frac{0}{3} \\x = 0$

d. $3x - 4 + 1 = - 2x -5 + 5x\\$

$3x - 3 = - 7x -5\\3x + 7x = 3 - 5\\10x = -2\\x = \frac{-2}{10} \\x = -\frac{1}{5}$

<em>The value of x in each </em><em>equation</em><em> are:</em>

<em /> $a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}$

Learn more here:

brainly.com/question/1527981

5 0

3 years ago

Last question of my homework pls <3

dimaraw [331]

Answer:

J(2, 5 )

Step-by-step explanation:

Using the section formula

$x_{J}$ = $\frac{1(-2)+2(4)}{2+1}$ = $\frac{-2+8}{3}$ = $\frac{6}{3}$ = 2

$y_{J}$ = $\frac{1(1)+2(7)}{2+1}$ = $\frac{1+14}{3}$ = $\frac{15}{3}$ = 5

Thus J = (2, 5 )

7 0

3 years ago

The temperature on Mars is -85°F and the temperature in the clouds of Jupiter is

Burka [1]

It’s b because it’s -85 f so the planet is colder

6 0

3 years ago

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago