Answer:
x = 2/3 or x = -1
Step-by-step explanation by completing the square:
Solve for x:
3 x^2 + x - 2 = 0
Divide both sides by 3:
x^2 + x/3 - 2/3 = 0
Add 2/3 to both sides:
x^2 + x/3 = 2/3
Add 1/36 to both sides:
x^2 + x/3 + 1/36 = 25/36
Write the left hand side as a square:
(x + 1/6)^2 = 25/36
Take the square root of both sides:
x + 1/6 = 5/6 or x + 1/6 = -5/6
Subtract 1/6 from both sides:
x = 2/3 or x + 1/6 = -5/6
Subtract 1/6 from both sides:
Answer: x = 2/3 or x = -1
12 bro it even says to follow the order of operations. If there is only addition and subtraction you just go from left to right. Same with if there is only multiplication and division.
the answer is 5 bebe. remember to use pemdas
p-parenthesis
e-exponents
m-multiplication
d-division
a-addition
s-subtraction
Beforehand let me apologize for my sloppy handwriting. I'm a lefty, so please deal with me. . Anyway, the equation you listed didn't really have a x, because a linear equation is y= mx+b, and anything with x is the slope. But I did see y and a number on one side, so I'm like maybe I can get these two alone. So here's what I did:
2y + 4=0
-4 -4 I subtracted 4 on both sides. Why because you would want "y" alone.
Next,
2y= -4
Now to get "y" alone you want to divide on both sides.
2y= -4/ 2
y= -2
Now you're probably thinking "how do you graph it? There's no "x" in the equation." Well, you just graph it. Since the answer is y= -2, you go to the y axis, look for -2, and place a line to indicate that is the equation. And to make it clear, remember y is the y-intercept.
I really do hope this helps you, if not message me. I'll be happy to help, and again I'm sorry for my handwriting!