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oksano4ka [1.4K]
2 years ago
8

The area of a triangular block is 81 square inches. If the base of the triangle is twice the height, how long are the base and t

he height of the triangle?
Mathematics
1 answer:
Gre4nikov [31]2 years ago
5 0

Answer:

18 inches and 9 inches

Step-by-step explanation:

Given, The base of a triangle is twice of the height.

Area = 81 sq inches

Let, Base (b) = 2x

Height (h) = x

Area of the triangle = \frac{1}{2}bh

\frac{1}{2}bh = 81

or, x^{2} = 8

Base = 2×9 inches = 18 inches

Height = 9 inches

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Answer:

7abc^{2}

Step-by-step explanation:

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3 years ago
Find the equivalent expression 5^6
Naily [24]
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Fofino [41]
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3 0
3 years ago
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umka2103 [35]

Answer:

34 goes in the blank.

Step-by-step explanation:

Triangle ABC is congruent to triangle TUV implies the following:

Angle A is congruent to angle T.

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Side AB is congruent to side TU.

Side BC is congruent to side UV.

Side CA is congruent to side VT.

Note: Order tells you everything in a congruence statement.

Since side BC is congruent to UV, then the measure of side BC is equal to the measure of side UV.

8x+2=7x+6

Subtract 7x on both sides:

1x+2=6

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Subtract 2 on both sides:

x=6-2

x=4

So if x=4, then the measure of side BC is 8x+2=8(4)+2=32+2=34.

So the measure of BC is 34 cm.

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3 years ago
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Step-by-step explanation: hope this helps

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