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2 years ago

Dad spends $227.06 at the grocery store,$95.55 at the shoe store,and $35.16 at the dry cleaners how much did dad spend in all?

Mathematics

2 answers:

nataly862011 [7]2 years ago

6 0

Answer:

$357.77

Step-by-step explanation:

Add all of the figures together to find the answer

227.06 + 95.55 + 35.16 = 357.77

azamat2 years ago

5 0

Answer:

227.06+95.55+35.16

$=357.77

Step-by-step explanation:

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18y4, 27y", and 63y?

lina2011 [118]

Answer:

$9y$

Step-by-step explanation:

If you are asking for the Greatest Common Factor [GCF], then here you go. All coefficients are divisible by 9...:

63: 1, 7, 9, 63

27: 1, 3, 9, 27

18: 1, 2, 3, 6, 9, 18

...and you take the LEAST DEGREE TERM POSSIBLE.

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5 0

3 years ago

4x+4=-2x+10 Alguien que me explique porfas ,el mejor doy corona

ehidna [41]

Answer:

X = 1

Step-by-step explanation:

$4x+4=-2x+10 \\4 - 10 = - 2x - 4x \\ - 6 = - 6x \\ - 6x = - 6 \\ x = \frac{ - 6}{ - 6} \\ x = 1$

6 0

2 years ago

Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE

AVprozaik [17]

Answer:

Step-by-step explanation:

We are given that:

$\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi$

And we want to find the value of tan(2x).

Note that since x is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

$\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}$

Using double angle identities:

$\displaystyle \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}$

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(x) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

$\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}$

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since x is in QII, cosine and tangent will be negative while sine will be positive. Hence:

<h2> $\displaystyle \tan(2x)=\frac{2(2\sqrt{2}/3)(-1/3)}{(-1/3)^2-(2\sqrt{2}/3)^2}$ </h2>

Simplify:

$\displaystyle \tan(2x)=\frac{-4\sqrt{2}/9}{(1/9)-(8/9)}$

Evaluate:

$\displaystyle \tan(2x)=\frac{-4\sqrt{2}/9}{-7/9} = \frac{4\sqrt{2}}{7}$

The final answer is positive, so we can eliminate A and B.

We can simplify D to:

$\displaystyle \frac{2\sqrt{8}}{7}=\frac{2(2\sqrt{2}}{7}=\frac{4\sqrt{2}}{7}$

So, our answer is D.

7 0

3 years ago

If q(x)=7x^2-1 find q(-9)

liq [111]

For this, we are just going to plug in -9 for every x and then solve the equation:

$q(x)=7x^{2} -1$

$q(-9)=7(-9)^{2} -1$

$q(-9)=7(81)-1$

$q(-9)=566$

Now we know that q(-9) is equal to 566.

3 0

3 years ago

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t

WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

$\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}$

Seperate the differential equation and solve for the constant C.

$\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}$

You have 100 rodents when:

$100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months$

You have 1000 rodents when:

$1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months$

7 0

3 years ago