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mash [69]
2 years ago
8

Two numbers are in the ratio of 10:16 if the sum of numbers is 572 find the numbers.

Mathematics
2 answers:
Semenov [28]2 years ago
7 0

Answer:

yo dude dont be upset im doing what you did lol!

irakobra [83]2 years ago
3 0
hey there

The given ratio is 10:16

Let two number be 10x and 16x

Also given sum is 572

=> 10x+16x=572

=> 26x=572

=> x = 572/26 = 22

Now the first number is 10x = 10(22) = 220 and
Another number is 16x = 16(22) = 352

Hope this helps you dear ;)
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Find the quotient of <br><br> -85^2-27n+76 / -17n-19
bagirrra123 [75]
<u><em>Answer:</em></u>
5n-4

<u><em>Explanation:</em></u>
<u>The given expression is:</u>
\frac{-85n^2-27n+76}{-17n-19}

<u>1- Take the negative as a common factor from both the numerator and the denominator. This will give us:</u>
\frac{-(85n^2+27n-76)}{-(17n+19)}

<u>2- Cancel out the negative sign (common factor) from the numerator and denominator. This will give us:</u>
\frac{(85n^2+27n-76)}{(17n+19)}

<u>3- Factor the numerator. This wil give:</u>
\frac{(5n-4)(17n+19)}{(17n+19)}

<u>4- Finally, cancel out the (17n+19) which common in both numerator and denominator. This will give us the final expression:</u>
5n-4

Hope this helps :)
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