Answer:
30 with extra
Step-by-step explanation:
It would be 29 and a little more but she would need 30 and have leftovers.
Answer:
1. ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y)
2. ∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
Step-by-step explanation:
If we negate a quantified statement, first we negate all the quantifiers in the statement from left to right, ( keeping the same order ) then we negative the statement,
Here, the given statement,
1. ∃y ∈Z such that ∀x ∈Z, R (x + y)
By the above definition,
Negation of this statement is ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y),
2. Similarly,
The negation of statement ∀x ∈Z, ∃y∈Z such that R(x + y),
∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
Answer:
Step-by-step explanation:
From the given attachment to the question, the following can be deduced.
1. M is the midpoint of GH, given that M is the definition of midpoint.
2. GM ≅ MH, given that x = 2. So that,
GM = 5x = 5(2)
= 10
MH = 3x + 4 = 3(2) + 4
= 10
Thus, GM ≅ MH
3. GM = MH is the definition of congruence. This implies that they are similar.
4. 5x = 3x + 4, by substitution property of equality.
Since, x = 2 then;
5(2) = 3(2) + 4
10 - 10
5. 2x = 4, given that x = 2.
6. GH = GM + MH, by division property of equality.
Printed pages in 11 minutes = 33 pages
Printed pages in a minute = 33/11
= 3 pages/minute
