Question

The table shows the weights of giant pumpkins grown in two towns, Cedartown and Baytown. Match each phrase to its value. Weight of Cedartown Weight of Baytown Pumpkins (pounds) Pumpkins (pounds) 611 584 753 622 575 713.5 685.5 579 718 644 20.2 40 40.2 60.4 575 628.5 668.5 713.5 the average weight of pumpkins grown in Cedartown 22 Edmentum.​

Answer 1

Average and mean absolute deviation of pumpkins grown in Cedartown: 668.5; 60.4

Average and mean absolute deviation of pumpkins grown in Baytown: 628.5; 40.2

What is the Mean Absolute Deviation?

The average distance of each point from the mean of a data is the absolute mean deviation.

Mean and mean absolute deviation of pumpkins grown in Cedartown:

611, 753, 575, 685.5, 718

Average/Mean = (611 + 753 + 575 + 685.5 + 718)0/5

Average/mean = 3342.5/5 = 668.5

Mean absolute deviation = [(611 - 668.5) + ( 753 - 668.5) + ( 575 - 668.5) + ( 685.5 - 668.5) + ( 718 - 668.5)] / 5

Mean absolute deviation = [(57.5) + (84.5) + (93.5) + (17) + (49.5)]/5 = 302/5

Mean Absolute Deviation = 60.4

Mean and mean absolute deviation of pumpkins grown in Baytown:

584, 622, 713.5, 579, 644

Average/Mean = (584 + 622 + 713.5 + 579 + 644)/5

Average/mean = 3142.5/5 = 628.5

Mean absolute deviation = [(584 - 628.5) + ( 622 - 628.5) + ( 713.5 - 628.5) + ( 579 - 628.5) + ( 644 - 628.5)] / 5

Mean absolute deviation = [(44.5) + (6.5) + (85) + (49.5) + (15.5)]/5 = 201/5

Mean Absolute Deviation = 40.2

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