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Ivenika [448]
3 years ago
5

If the domain is {0, 2, -6}, what is the range of y = -2x + 3?

Mathematics
2 answers:
jasenka [17]3 years ago
6 0

Answer:

what is a domain

Step-by-step explanation:

please explain sorry

schepotkina [342]3 years ago
5 0

Answer:

the rage is 1 this should be the answer

Step-by-step explanation:

Y=-2x+3?

Y= -2 -2

X=1

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vaieri [72.5K]

Answer:

1

Step-by-step explanation:

10³/10³

10³-³

10⁰=1

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4 0
2 years ago
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B
VARVARA [1.3K]

Answer:

Hypothenus = 22

Step-by-step explanation:

From the question given above, we were told that the triangles are congruent (i.e same size). Thus,

AC = EF

BC = DE

To obtain the length of each Hypothenus, we shall determine the value of y and x. This can be obtained as follow:

For y:

AC = y + 3

EF = 2y + 1

AC = EF

y + 3 = 2y + 1

Collect like terms

3 – 1 = 2y – y

2 = y

y = 2

For x:

BC = 5x + 7

DE = 6x + 2y

y = 2

DE = 6x + 2(2)

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Collect like terms

7 – 4 = 6x – 5x

3 = x

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Finally, we shall determine the length of each Hypothenus. This can be obtained as follow:

Hypothenus = BC

Hypothenus = 5x + 7

x = 3

Hypothenus = 5x + 7

Hypothenus = 5(3) + 7

Hypothenus = 15 + 7

Hypothenus = 22

OR

Hypothenus = DE

DE = 6x + 2y

y = 2

x = 3

Hypothenus = 6(3) + 2(2)

Hypothenus = 18 + 4

Hypothenus = 22

5 0
3 years ago
Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

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\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
2 years ago
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The answer to the problem is 4 over 52

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3 0
2 years ago
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Oliga [24]

Answer:

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Step-by-step explanation:

1. False; the ball was not still in the air at 1 second the x-component of the vertex is 0.5.

2. False; the x-component of the vertex is 0.5

3. True; the ball was tossed at a height of 2 feet (when x=0, y=2), it is safe to assume the ball was caught at the same height.

4. False; when x = 0, y = 2.

8 0
2 years ago
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