the volume of the triangular prism will be, the area of the triangular face times its length
![\stackrel{\textit{area of the triangle}}{\left[ \cfrac{1}{2}(\underset{b}{8})(\underset{h}{8}) \right]}~~ ~~\stackrel{length}{(x)}~~ = ~~\stackrel{volume}{576}\implies 32(x)=576 \\\\\\ 32x=576\implies x=\cfrac{576}{32}\implies x=18](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20triangle%7D%7D%7B%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cunderset%7Bb%7D%7B8%7D%29%28%5Cunderset%7Bh%7D%7B8%7D%29%20%5Cright%5D%7D~~%20~~%5Cstackrel%7Blength%7D%7B%28x%29%7D~~%20%3D%20~~%5Cstackrel%7Bvolume%7D%7B576%7D%5Cimplies%2032%28x%29%3D576%20%5C%5C%5C%5C%5C%5C%2032x%3D576%5Cimplies%20x%3D%5Ccfrac%7B576%7D%7B32%7D%5Cimplies%20x%3D18)
Answer: Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
area of 1/6 circle:
= 1/6 * 3.14 * 8^2
= 33.49 ft^2
area of equilateral triangle:
= √3/4 * 8^2
= 27.71 ft^2
Area of shaded = area of 1/6 circle - area of equilateral triangle
= 33.49 - 27.71
= 5.78
= 5.8 ft^2
answer
B. 5.8 ft^2
The length would be:
120-2(20)=2x
Then you would solve for x.
120-40=2x
80=2x
x=40, so the length is 40 yards.
