Answer:
Step-by-step explanation:
h = -6 +20t + 4
 +20t + 4
I will use calculus,  maybe that's not how you're supposed to do this
-12t +20 =0 
12t = 20
t = 20 /12
t = 1 
t = 1 
there will be a max at  1.6666666666  seconds
-6* + 20 * 1.6666666666  +4
  + 20 * 1.6666666666  +4
= 16.666666666666 + 33.333333333333 + 4
= - 16 + 33
 + 33  + 4
 + 4
= 20 feet max height ( not too high,  for a rocket)
  feet max height ( not too high,  for a rocket) 
time of flight:
0 = -6 +20t + 4
 +20t + 4
use quadratic formula to find t
-20 +- sqrt [  - 4*(-6)*4 ] / 2*(-6)
 - 4*(-6)*4 ] / 2*(-6) 
-20 +- sqrt [400 + 96 ] / -12 
-20 +- sqrt [496 ] / -12
-20 +- 22.27105 / -12
try the negative option 1st 
-42.27105 / -12
3.522 seconds.     time of flight
when will the rocket be at 12' ? :
12 = -6 +20t + 4
 +20t + 4
0 = -6 +20t -8
 +20t -8
use quadratic formula again to find t
-20 +- sqrt [  - 4*(-6)*(-8) ] / 2*(-6)
 - 4*(-6)*(-8) ] / 2*(-6)
-20 +- sqrt [ 400 - 192 ] / -12
-20 +- sqrt [208 ] / -12
-20 - 14.4222 / -12
-34.4222 / -12
2.8685 seconds ( on the way down)
and
-20 + 14.4222 / -12
-5.578 / - 12
0.4648  seconds ( on the way up )
 
        
             
        
        
        
Answer:
1,5,25,125, 
all can be added or multiplied to equal 125
 
        
             
        
        
        
Answer:
Step-by-step explanation:
x²+3x+2=0
x²+x+2x+2=0
x(x+1)+2(x+1)=0
(x+1)(x+2)=0
x=-1,x=-2
so B
 
        
             
        
        
        
Ya i think that it would bee