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miss Akunina [59]
2 years ago
13

A certain type of brass contains 65% copper. How many pounds of copper are contained in 120 pounds of brass?

Mathematics
1 answer:
enyata [817]2 years ago
7 0

The number of pounds of copper in 120 pounds of brass is = 78 pounds of copper

<h3>Calculation of number of pounds of copper</h3>

The percentage of copper in the brass = 65%

Therefore the quantity of copper in the brass = 65/100= 0.65 pounds

This means that 1 pound brass contains = 0.65 pounds of copper

The quantity of copper in 120 pounds of brass = 120 * 0.65

                                                                             = 78 pounds of copper.

Learn more about copper here:

brainly.com/question/24856041

#SPJ1

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Solve the following absolute value equation for the unknown. Show all of your work for full credit. |-3h – 6| ≤ 3
ss7ja [257]

Answer:

-3 \le h \le 1.

Step-by-step explanation:

Apply the property of absolute values: if a \ge 0, then |x| \le a \iff -a \le x \le a. By this property, |- 3\, h - 6 | \le 3 is equivalent to -3 \le -3\, h - 6\le 3. That's the same as saying that -3\, h - 6 \ge -3 and -3\, h - 6 \le 3.

Add 6 to both sides of both inequalities:

-3\, h \ge 3 and -3\, h \le 9.

Divide both sides of both inequalities by (-3). Note that because -3 < 0, dividing both sides of an equality by this number will flip the direction of the inequality sign.

  • -3\, h \ge 3 would become h \le -1.
  • -3\, h \le 9 would become h \ge -3.

Both inequalities are supposed to be true. Combining the two inequalities to obtain:

-3 \le h \le 1.

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4 years ago
What is 1000m in 2 minutes?
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3 years ago
A car dealership has 55 cars and 11 vans. What is the ratio of cars to vans?
JulijaS [17]
It is 55:11. What number can both those numbers divide by? 11.
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3 years ago
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Solve the following 3 × 3 system. Enter the coordinates of the solution below.
defon

9514 1404 393

Answer:

  (x, y, z) = (-1, 0, -3)

Step-by-step explanation:

We notice that the coefficients of z are such that elimination of the z term from the equations is made easy.

Adding equations 1 and 2:

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Adding equations 2 and 3:

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Substituting for x, we get ...

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Then z can be found from any equation. Substituting for x and y in the second equation gives ...

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  z = -3 . . . . . .divide by 2

The solution is (x, y, z) = (-1, 0, -3).

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