Answer:
A. car needing both repairs is the intersection, which is P(A) * P(B).
92/200 * 136/200 = 391/1250 = .3128
B. car needing an alternator and not needing new brakes is the union, which is P(A) + P(notB) - P(A and B). We solved for P(A and B) in part A.
P(A) + P(notB) - P(A and B)
136/200 + 108/200 - .3128 = .9072
Answer: 1:6
Step-by-step explanation: if the die is 6-sided then the probability of it landing on one certain side is 1 out of those six sides.
Answer: he completed he completed 103.5 push ups in 45 seconds
Answer: 25/676
Step-by-step explanation:
Number of possible outcomes = 26
In other to win, one must draw must be either (A, E, I, O or U)
Therefore required drws to win = 5
First draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Second draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Therefore,
P(winning twice) = (5/26) × (5/26) = 25/676
