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Tema [17]
3 years ago
11

On Sunday the temperature was 52 degrees and on Tuesday it was -10 degrees. What was the difference in temperature from Sunday t

o Tuesday?
Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

<h2>62</h2>

Step-by-step explanation:

<em>The answer is 62.</em>

<em>Here's an example.</em>

<em>52 - ( -10 ) = 62</em>

<em>So, the difference in temperature from Sunday to Tuesday is 62.</em>

<em></em>

<em>Just to let you know.</em>

<em>( -10 ) - 52 = -62 ( This is not the answer )</em>

<em>Remember that 62 is the answer.</em>

<em>Hope this helps! <3</em>

Nina [5.8K]3 years ago
5 0
The difference was 62 degrees.
52 - (-10) = 62
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Masteriza [31]
You know that there are 60 minutes in one hour, so you multiply 34 x 60.
4 0
3 years ago
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Juanita is cutting a piece of construction paper in the shape of a parallelogram. Two opposite sides of the parallelogram have l
Tema [17]

Answer:

4 cm and 7 cm

Step-by-step explanation:

Given that Juanita is cutting a piece of construction paper in the shape of a parallelogram. Two opposite sides of the parallelogram have lengths (5n − 6) cm and (3n − 2) cm.

We know that opposite sides are equal in a parallelogram.

Hence we have

5n-6 = 3n-2\\2n =4\\n=2

Hence the side length = 5(2)-6 =4 cm

The adjacent side = 2n+3\\=2(2)+3\\=7cm

Thus answer is 4 cm and 7 cm

3 0
3 years ago
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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?
gladu [14]
Sum:

     3x^5*y - 2x^3*y^4 - 7x*y^3
 + -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
     -5x^5y - 6xy^3

Term 1: Degree = 6
Term 2: Degree = 4

Difference:

     3x^5*y - 2x^3*y^4 - 7x*y^3
 -  -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
     11x^5y - 4<span>x^3*y^4 - 8</span>xy^3

Term 1: Degree = 6
Term 2: Degree = 7
Term 3: Degree = 4

The degree of a term of a polynomial can be obtained by adding the exponents of the variables in that term.
5 0
3 years ago
Show me how you solve it
julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u>

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n} }

Therefore:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  }

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{( {a}^{m} ) ^{n} =  {a}^{m \times n}  }

Thus:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  = {5}^{5 \times 4}   } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =   {5}^{20} }

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3 years ago
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8/8-5/8 = 3/8 Which Is Equivalent To The Amount Of Cake Left Over And The Amount Of Cake That Dennis Ate

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