Given: Different points and an angles as found in the image
To Determine: The correct name of the angle shown
Solution
An angle is formed when two lines meet at a point. This is as shown below
Let us apply the above to the given image
The angle formed is shown by the red arc.
Hence, the correct name of the angle shown is ∠
Sqrt of 125
10^2 +b^2= 15^2
100 +b^2=225
B^2=125
No perfect square for 125 so leave it in radical form
Answer:
-15
Step-by-step explanation:
We have the expression 3(2p - 5) - 6p and are asked to simplify.
Let's distribute, which is to multiply a number that is outside of a parenthesis bracket by the numbers inside the parenthesis.
3(2p - 5) - 6p
(3(2p) - 3(5)) - 6p
6p - 15 - 6p
Since you can only do changes to like terms and 15 and 6p are two different terms, we do 6p - 6p.
6p - 6p
0
Leaving us with -15.
I think the answer is b 0.2(20)
Answer:
1. -4(6)= -24
2.-21-8= -29
3. 121-4 =117
4. -6(5) =-30
5. -10(-9)= 90
6. (-5)7= -35
7. (-5)8= -40
8. -30(5)= -150
9. 20(-6)= -120
10. -14(6)= -84
11. (-13)2 = -26
12. –7(15) = -105
13. -3(4) = -12
14. 7(-3) = -21
15. 3(-3) = -9
16. -2(-10) = 20
17. (-5)(-3)(4) = 60
18. -3(-3)(4)= 36
19. -3(-5) = 15
20. 5(-3) = -15
21. 7(-5)(4) = -140
22. -2(-5)(-3)= -30
23. – 10(-3)=30
24. -21-3= -24
Explanation:
We have followed the rules in adding and subtracting negative as well as positive values on the number line.
When adding two negative values, the result is a negative value.
When adding a negative and positive value, the result is either a positive or negative value depending on if the negative value is bigger or smaller than the positive value
When multiplying two negative values, the result is a positive value
When multiplying one negative and one positive value, the result is a negative value
To make you understand addition and subtraction of negative and positive numbers better, let us use a simple analogy. Assuming you are owing five oranges(-5) and you are only able to give two oranges(+2), you will still be owing 3 oranges(-3). Assuming also that you are owing 6 oranges(-6) and you are able to give 8 oranges(+8), you would have given excess oranges and would be owed two oranges(+2). Hence the results above.
