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spayn [35]
2 years ago
14

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (negative 2, 3) an

d (0, negative 1). Everything to the left of the line is shaded. The second dashed line has a negative slope and goes through (0, 2) and (1, 0). Everything to the right of the line is shaded.
Which inequality pairs with y≤−2x−1 to complete the system of linear inequalities represented by the graph?

y<−2x+2
y>−2x+2
y<2x−2
y>2x−2
Mathematics
2 answers:
chubhunter [2.5K]2 years ago
7 0

Answer:

To graph the inequality

y < 2x - 5

we graph the dashed boundary line y=2x-5 with a positive slope of 2 and y-intercept (0,-5) and shade everything to the right.

To graph the inequality y>-3x+1, we graph the dashed boundary line y=-3x +1 with y-intercept (0,1) and shade every above it.

The intersection of the two shadings is the solution to the system of inequalities:

y < 2x - 5

and

y > -3x + 1

Simora [160]2 years ago
6 0
Y>-2x+2 but i aint gon lie it didn’t tell me if i got it wrong or right g
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Write the equation of the line that passes through (0,-6) and (4,10)
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