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spayn [35]
2 years ago
14

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (negative 2, 3) an

d (0, negative 1). Everything to the left of the line is shaded. The second dashed line has a negative slope and goes through (0, 2) and (1, 0). Everything to the right of the line is shaded.
Which inequality pairs with y≤−2x−1 to complete the system of linear inequalities represented by the graph?

y<−2x+2
y>−2x+2
y<2x−2
y>2x−2
Mathematics
2 answers:
chubhunter [2.5K]2 years ago
7 0

Answer:

To graph the inequality

y < 2x - 5

we graph the dashed boundary line y=2x-5 with a positive slope of 2 and y-intercept (0,-5) and shade everything to the right.

To graph the inequality y>-3x+1, we graph the dashed boundary line y=-3x +1 with y-intercept (0,1) and shade every above it.

The intersection of the two shadings is the solution to the system of inequalities:

y < 2x - 5

and

y > -3x + 1

Simora [160]2 years ago
6 0
Y>-2x+2 but i aint gon lie it didn’t tell me if i got it wrong or right g
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IRISSAK [1]
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X=85

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No.7
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No.9
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7 0
2 years ago
Which is a stretch of an exponential decay function?
NNADVOKAT [17]

Answer:

The correct option is 3. The function  is a stretch of an exponential decay function.

Step-by-step explanation:

The general form of an exponential function is

where, a is the initial value and b is the growth factor.

If b<1, then it represents a decay function and if b>1, then it represents a growth function.

Let k be a stretch and compression factor.

If k<1, then it represents vertical compression and if k>1, then it represents vertical stretch.

In third function

Therefore the function  is a stretch of an exponential decay function.

7 0
3 years ago
Read 2 more answers
Pls help due at 5 slope
Vsevolod [243]

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5 0
3 years ago
Roman stands across from a flag pole.
tigry1 [53]
We have been given a right angled triangle, hypotenuse is known, and angle has been given. we need to find the adjacent side to the angle.

we use trigonometry ratios.
the ratio where we relate the hypotenuse and adjacent side is the cosine.
cos θ = adjacent side / hypotenuse 
where θ = 39°
hypotenuse - 17 m
adjacent side - x
we need to solve for x

cos 39° = x / 17
cos 39° = 0.77
0.7771 = x/17
x = 0.7771 x 17
x = 13.21 m
distance from Roman's feet to the base of the pole is 13.21 
6 0
3 years ago
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