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2 years ago

1. Draw an equilateral triangle whose each side is 4.5 cm

Mathematics

2 answers:

just olya [345]2 years ago

7 0

<h2>꧁༒Answer༒꧂</h2>

Answer is on the picture

Helen [10]2 years ago

5 0

Answer:

Step-by-step explanation:

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If 2c - d = 3d - 2c, what is d in terms of c

xz_007 [3.2K]

Answer:

4c=4d

-remember to change the signs/symbols and do the like terms

3 0

3 years ago

Para pertenecer al equipo de futbol femenino de una ciudad se deben presentar 18 pruebas y por cada prueba hecha de forma correc

GenaCL600 [577]

Answer:

150 scores

Step-by-step explanation:

The computation of the score did she get is shown below:

Since there is 18 test presented

And if the test is done on correct manner so 10 points should be awarded

Now since fifth-sixth would be done correctly

So,

= 18 × 5 ÷ 6 × 10

= 150 scores

7 0

3 years ago

How do you factor quadratics into binomials the question says

USPshnik [31]

X^2+9x+24=0 i believe, i’m only in 7th grade so

also, you factor the equation equal to zero and factor the left side

6 0

3 years ago

Read 2 more answers

What is the result of subtracting the second equation from the first?

Mashcka [7]

Answer:

The result is that you eliminate the 7y term and thus can solve for x.

x = -28/3

y = 30/7

Step-by-step explanation:

-20 + 7y = 10

3x + 7y = 2

subtract... elimination method

-20 - 3x = 8

-3x = 28

x = -28/3

-20 + 7y = 10

7y = 30

y = 30/7

3 0

3 years ago

Read 2 more answers

Approximately 80,000 marriages took place in the state of New York last year. Estimate the probability that for at least one of

sasho [114]

Answer:

a)0,45119

b)1

Step-by-step explanation:

For part A of the problem we must first find the probability that both people in the couple have the same birthday (April 30)

$P=\frac{1}{365} *\frac{1}{365}=\frac{1}{133225} \\$

Now the poisson approximation is used

λ=nP=80000*1/133225=0,6

Now, let X be the number of couples that birth April 30

P(X ≥ 1) =

1 − P(X = 0) =

$1-\frac{(e^-0.6)*(-0,6)^{0} }{0!}$

P(X ≥ 1) = 0,45119

B) Now want to find the

probability that both partners celebrated their birthday on th, assuming that the year is 52 weeks and therefore 52 thursday

$P=52*\frac{1}{365} *\frac{1}{365}=\frac{52}{133225} \\$

Now the poisson approximation is used

λ=nP=80000*52/133225=31.225

Now, let X be the number of couples that birth same day

P(X ≥ 1) =

1 − P(X = 0) =

$1-\frac{(e^-31.225)*(-31.225)^{0} }{0!}$

P(X ≥ 1) = 1

6 0

3 years ago