Answer:
<h2>V = 235.5 in³</h2>
Step-by-step explanation:
The formula of a volume of a cylinder:
![V=\pi r^2H](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E2H)
r - radius
H - height
From the pictue we have r = 5in and H = 3in. Substitute:
![x=\pi(5^2)(3)=\pi(25)(3)=75\pi\ in^3](https://tex.z-dn.net/?f=x%3D%5Cpi%285%5E2%29%283%29%3D%5Cpi%2825%29%283%29%3D75%5Cpi%5C%20in%5E3)
![\pi\approx3.14](https://tex.z-dn.net/?f=%5Cpi%5Capprox3.14)
Therefore
![x=(75)(3.14)=235.5\ in^3](https://tex.z-dn.net/?f=x%3D%2875%29%283.14%29%3D235.5%5C%20in%5E3)
Let
represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of
feet per second, and the miners one descends with a velocity of
feet per second.
If we start counting time (
) when the equipment elevator begins to descend, after
seconds its depth will be
![d_e(t) = v_et = 4t](https://tex.z-dn.net/?f=%20d_e%28t%29%20%3D%20v_et%20%3D%204t%20)
On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:
![d_m(t) = v_m(t-30) = 15(t - 30)](https://tex.z-dn.net/?f=%20d_m%28t%29%20%3D%20v_m%28t-30%29%20%3D%2015%28t%20-%2030%29%20)
Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when
. Let's plug this value into the two equations:
![d_e(44) = 4\cdot 44 = 176](https://tex.z-dn.net/?f=%20d_e%2844%29%20%3D%204%5Ccdot%2044%20%3D%20176%20)
![d_m(44) = 15(44-30) = 15\cdot 14 = 210](https://tex.z-dn.net/?f=%20d_m%2844%29%20%3D%2015%2844-30%29%20%3D%2015%5Ccdot%2014%20%3D%20210%20)
So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.
Answer:
8*8=64
Step-by-step explanation:
Don't worry! Keep on trying! I hope this helps! Have a great rest of your day!