19/15, look at the attachment for work
Answer:
533.33 ft/min
Step-by-step explanation:
We are given that
x=3 feet
y=4 feet
Height of person,h=6 feet

Triangle ABC and A'B'C are similar because all right triangles are similar
By using similarity property








Differentiate w.r.t t



Hence, If the person is 6 feet tall and walks away from the lamp post at a speed of 400 feet per minute then his shadow moving at the rate 533.33 ft/min
I think you need to rewrite your question
100mm÷60.2seconds=1.661129568mm per second