What is the distance between (22,-3) and (1, -3)?

Mathematics

1 answer:

Bingel [31]2 years ago

6 0

Answer:

Option D

Step-by-step explanation:

<h2>Distance between two points</h2>

The y-value of the two points is unchanged. So, the line is parralel to x-axis.

The distance will be the diffrence between the x-co ordinates.

$\sf Distance = 1 - (-2\dfrac{1}{2})$

$\sf =1+\dfrac{5}{2}\\\\= \dfrac{2}{2}+\dfrac{5}{2}\\\\=\dfrac{7}{2}\\\\=3\dfrac{1}{2}$

You might be interested in

Find the right quotient. 36m 5 n 5 ÷ (12m 3)

polet [3.4K]

ANSWER

The right quotient is

$3 {m}^{2} {n}^{5}$

EXPLANATION

The given expression is :

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} }$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = \frac{36}{12} \times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3\times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

Recall that,

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$
We apply this property to obtain;

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 \times {m}^{5 - 3} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 {m}^{2} {n}^{5}$

5 0

3 years ago

Read 2 more answers

Write an expression for the calculation subtract 10 divided into fifths from 20 diveded in half

vredina [299]

20/2-10/5. You divide 20 by 2 and subtract that from 10 divided by 5

5 0

3 years ago

Work out the value of 102 - 43<br> Give your answer as a power of 6.

Drupady [299]

Answer:

1.9730677676839334 or 1.97 (rounded)