Answer:
The product of the monomials is 2304 ![x^{5}](https://tex.z-dn.net/?f=x%5E%7B5%7D)
![y^{6}](https://tex.z-dn.net/?f=y%5E%7B6%7D)
Step-by-step explanation:
* <em>Lets explain how to solve the problem</em>
- We need to find the product of the monomials (8x 6y)² and
![x^{3}y^{4}](https://tex.z-dn.net/?f=x%5E%7B3%7Dy%5E%7B4%7D)
- At first lets solve the power of the first monomial
- Because the power 2 is on the bracket then each element inside the
bracket will take power 2
∵ (8x 6y)² = (8)²(x)²(6)²(y)²
∵ (8)² = 64
∵ (x)² = x²
∵ (6)² = 36
∵ (y)² = y²
∴ (8x 6y)² = [64x² × 36y²]
∵ 64 × 36 = 2304 x²y²
∴ The first monomial is 2304 x²y²
∵ The first monomial is 2304 x²y²
∵ The second monomial is ![x^{3}y^{4}](https://tex.z-dn.net/?f=x%5E%7B3%7Dy%5E%7B4%7D)
- Lets find their product
- Remember in multiplication if two terms have same bases then we
will add their powers
∵ [2304 x²y²] × [
] =
2304 [
] [
]
∵
=
= ![x^{5}](https://tex.z-dn.net/?f=x%5E%7B5%7D)
∵
=
= ![y^{6}](https://tex.z-dn.net/?f=y%5E%7B6%7D)
∴ [2304 x²y²] × [
] = 2304 ![x^{5}](https://tex.z-dn.net/?f=x%5E%7B5%7D)
![y^{6}](https://tex.z-dn.net/?f=y%5E%7B6%7D)
The product of the monomials is 2304 ![x^{5}](https://tex.z-dn.net/?f=x%5E%7B5%7D)
![y^{6}](https://tex.z-dn.net/?f=y%5E%7B6%7D)
We have that the total students there are 500. The 12-graders there are 200. Probability is defined as the ratio of positive outcomes of an event, over all the possible outcomes. Suppose we pick student randomly. Then, there are 200 positive outcomes (positive outcome: we pick a student in 12th grade) and there are totally 500 outcomes (we can pick 500 students in total from Riverside High School). This ratio gives:
![P= \frac{200}{500} =0.4](https://tex.z-dn.net/?f=P%3D%20%5Cfrac%7B200%7D%7B500%7D%20%3D0.4)
. The requested probability is 0.40
Answer:
5x + 20 + (-20) = 5x
Step-by-step explanation:
Opposite of 20 is just -(20) which is -20.
5x + 20 + (-20) = 5x + 20 -20 = 5x
Answer:
wertyuiopjhgfdsw3456789pl,mnbgte78ywhhgr6ydusn56tnhfvbnbfgd
Step-by-step explanation: