Answer:
A. 50°
Step-by-step explanation:
The external angle ACB created by tangents CA and CB is the supplement of arc AB it intercepts.
∠ACB = 180° -AB
∠ACB = 180° -130°
∠ACB = 50°
Answer:
(6, 0) is located on the x-axis
Explanation:
For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.
"(0, 5) is located at the origin" is not true because the origin is at (0, 0).
"(0, 5) is located on the x-axis" is not true because its y-value is 5, not 0.
"(6, 0) is located at the origin" is not true because the origin is at (0, 0).
Answer:
8
Step-by-step explanation:
Substitute 3 for x
-2x + 14
-2(3) + 14
-6 + 14 = 8
Answer:
BC=EC(GIVEN)
AC=DC(GIVEN)
<BCA=<DCE(VERTICAL OPPOSITE ANGLE)
BCA=DCE(BY SAS CRITERIA)
BA=DE(BY CPCT )
C. 68°
292° lies on 4th quadrant.
<h3><u>Reference angle</u>:</h3>
1st quadrant: angle
2nd quadrant: 180° - angle
3rd quadrant: angle - 180°
4th quadrant: 360° - angle
So, reference angle: 360° - 292° = 68°
