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Mazyrski [523]
3 years ago
5

Formula of Santander deviation .​

Mathematics
2 answers:
joja [24]3 years ago
4 0

Answer:

Step-by-step explanation:

kolbaska11 [484]3 years ago
4 0

Answer:

Work out the Mean(the simple average of the numbers)

Then for each number: subtract the Mean and square the result.

Then work out the Mean of those squared differences.

Take the square root of that and we are done!

Step-by-step explanation:

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Triangle X Y Z is shown. The length of side X Y is (9 n + 12) feet and the length of side X Z is (15 n minus 6) feet. Angles X Y
zmey [24]

Answer:

n = 3

XY = 39

XZ = 39

Step-by-step explanation:

Given

XY = 9n + 12

XZ = 15n - 6

Solving (a): n

To solve for n;

We make use of

XY = XZ

Substitute values for XY and XZ

9n + 12 = 15n - 6

9n - 15n = -12 - 6

-6n = -18

Divide through by -6

n = 3

Solving (b) XY

XY = 9n + 12

Substitute 3 for n

XY = 9 * 3 + 12

XY = 27 + 12

XY = 39

Solving (c): XZ

XZ = XY

XZ = 39

7 0
3 years ago
Does the table below represent a function?
NikAS [45]

Answer:

a) Yes.

Step-by-step explanation:

A function does not have any repeating values for a given x-value. According to the values of the table, there aren't multiple y-values for a given x-value. Therefore, the table represents a function.

4 0
2 years ago
Read 2 more answers
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi
stealth61 [152]
Applying our power rule gets us our first derivative,

\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}

simplifying a little bit,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

looking for critical points,

\rm 0=2x^{-2/3}+4x^{1/3}

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

0=2x^{-2/3}\left(1+2x\right)

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

and take our second derivative.

\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}

Looking for inflection points,

\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}

Again, pulling out the smaller power of x, and fractional part,

\rm 0=-\frac43x^{-5/3}\left(1-x\right)

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.
8 0
3 years ago
During a three-day period, the stock of Money, Inc. gained 6 points, lost 10 points, and gained 2 points. What was the total cha
hjlf
It didn’t have no gaining
4 0
3 years ago
Read 2 more answers
Helpppp :,[ also stay safe and have a great day!!!!!!!!!!!!!!!!!!!!!!1111
serious [3.7K]

Answer:

35÷7=5

Step-by-step explanation:

we have 7 small boxes in an oval and there are 5 ovals

All the boxes add up to 35

4 0
3 years ago
Read 2 more answers
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