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Aleonysh [2.5K]
2 years ago
15

Two functions are shown below.

Mathematics
2 answers:
vodka [1.7K]2 years ago
6 0

Answer:

  x = 6

Step-by-step explanation:

We assume your functions are ...

  • f(x) = (1/2)(2^x)
  • g(x) = 5x+2

In general, mixed polynomial and exponential functions have no algebraic solution. That means we need to solve f(x) = g(x) using a table of values, or by graphing.

__

Attached is a graphical solution. It shows the largest value of x for which f(x) = g(x) is x=6.

<em>Check</em>: f(6) = 1/2(2^6) = 32 = g(6) = 5(6) +2

__

<em>Additional comment</em>

We can start with f(x) = g(x) and subtract g(x) from both sides of the equation. This gives ...

  f(x) -g(x) = 0

Many graphing calculators readily identify the zeros of a function or expression. We have used that fact to find the two values of x where these functions are equal: ≈0.32 and 6.

For x>6, the exponential function increases without bound, so the graphs never cross again. Likewise, for x < -0.32, the linear function decreases without bound, so the graphs never cross again.

The lower value of x where the graphs cross is an irrational number near −0.319886722135.

ELEN [110]2 years ago
5 0

Answer:

x = 6

Step-by-step explanation:

As the function f(x) is an exponencial function, it will grow faster than g(x), that is a linear function.

For small values of x, we have that f(x) < g(x). For example:

f(1) = 1/2 * 2 = 1

g(1) = 5*1 + 2 = 7

f(2) = 1/2 * 4 = 2

g(2) = 5*2 + 4 = 14

So we just need to check some integer values and see when f(x) will be bigger than g(x). It will not be a big value, as the exponencial function grows very fast.

For x = 5, we have:

f(5) = 1/2 * 32 = 16

g(5) = 5*5 + 4 = 29

For x = 6, we have:

f(6) = 1/2 * 64 = 32

g(6) = 5*6 + 4 = 34

For x = 7, we have:

f(7) = 1/2 * 128 = 64

g(7) = 5*7 + 4 = 39

So the largest integer value of x for f(x) ≤ g(x) is x = 6.

Another way to solve this is by plotting both equations, and then checking where they cross, that is, where f(x) = g(x).

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a catering service offers 6 appetizers, 10 main courses, and 8 desserts. A banquet committee is to select 2 appetizers, 3 main c
S_A_V [24]

There are two different answers that you could be looking for.
You might be asking how many different meals can be served at the banquet,
or you might be asking literally how many 'ways' there are to put meals together.

I'm going to answer both questions.  Here's how to understand the difference:

Say you have ten stones, and you tell me "I'll let you pick out two stones
and take them home.  How many ways can this be done ?"

For my first choice, I can pick any one of 10 stones.  For each of those . . .
I can pick any one of the 9 remaining stones for my second choice.
So the total number of 'ways' to pick out two stones is  (10 x 9) = 90 ways.

But let's look at 2 of those ways:
   -- If I pick stone-A first and then pick stone-G, I go home with 'A' and 'G'.
   -- If I pick stone-G first and then pick stone-A, I still go home with 'A' and 'G'.
There are two possible ways to pick the same pair.
In fact, there are two possible ways to pick <em><u>every</u></em> pair.
So there are 90 <em><u>ways</u></em> to pick a pair, but only 45 different pairs.

That's the reason for the difference between the number of <em><u>ways</u></em> the
committee can make their selections, and the number of different <em><u>meals</u></em>
they can put together for the banquet.

So now here's the answer to the question:

-- Two appetizers can be selected in (6 x 5) = 30 ways.
(But each pair can be selected in 2 of those ways,
so there are only 15 possible different pairs.)

-- Three main courses can be selected in (10 x 9 x 8) = 720 ways.
(But each trio can be selected in 3*2=6 of those ways,
so there are only 120 possible different trios.)

-- Two desserts can be selected in (8 x 7) = 56 ways.
(But each pair of them can be selected in 2 of those ways,
so there are only 28 possible different pairs.)

-- The whole line-up can be selected in (30 x 720 x 56) = <em>1,209,600 ways</em>.

But the number of different meals will be  (30 x 720 x 56) / (2 x 6 x 2) =

                                                                   (15 x 120 x 28) =  <em><u>50,400 meals</u></em>.



5 0
3 years ago
A bow is made from 2 2/3 yards of ribbon. Which expression gives the number of bows that can be made from 22 5/8 yards?
iren2701 [21]

Answer:

2 2/3=(6+2)/3=8/3

22 5/8=(176+5)/8=181/8

the  expression will be 181/8 : 8/3=181/8*3/8=181*3/8*8= 543/64

Step-by-step explanation:

6 0
3 years ago
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8 0
4 years ago
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musickatia [10]

Answer:

18

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-2(3x+4)+7x=10

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x=10+8

x=18

6 0
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