To do this problem you would need to have at least one side length AND the hypotenuse to figure out the other side length.
Answer:
5(3x+2)-2(4x-1)
15x+10-8x+2
7x+12
Step-by-step explanation:
You need to find a common factor that both the
numerator
and denominator have. 16 and 12 have common divisible factors of 2 and 4(excluding 1, because 1 is self-defined but doesn't simplify values at all).
We use the highest factor, in this case, 4.
Divide 16 by 4 and 12 by 4.
16/4 = 4
12/4 = 3
We put 4 in place of the numerator and 3 in place of the denominator.
The width of the big dog house is 2.5 times the small dog house.
multiply 2 by 2.5 to get your answer. hope this helps :)